3 years ago

-7x-27=8-1(x-19) show how to get this

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

$-7x-27=8-1(x-19) \\
-7x-27=8-x+19\\
-6x=54\\
x=-9$

You might be interested in

^ { (5x ^ { 3 } -7x ^ { 2 } +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }

Tomtit [17]

Answer:

$-3x^{3} -9x^2+3$

Step-by-step explanation:

Given

$(5x^{3} -7x^{2} +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }$

Required

Simplify

$(5x^{3} -7x^{2} +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }$

Open brackets

$5x^{3} -7x^{2} +3x-4-8x^3 -2x^2 -3x+7$

Collect Like Terms

$-8x^3+5x^{3} -7x^{2} -2x^2+3x -3x-4+7$

Simplify like terms

$-3x^{3} -9x^2+3$

6 0

2 years ago

If xy = 0, what must be true about either x or y?

koban [17]

Answer:

One of them must be zero.

Step-by-step explanation:

For something to equal zero it needs to be multiplied by a value of zero.

4 0

3 years ago

Read 2 more answers

Are the following equations parallel y=1/3x+6 and y=1/3x+12 ?

Mademuasel [1]

Answer: yes

Step-by-step explanation:

They run side by side together

5 0

2 years ago

Read 2 more answers

Solve the inequality 15 ≥ q + 3

oksano4ka [1.4K]

Answer:

$q\le \:12$

Step-by-step explanation:

<u>Solving</u>

$\mathrm{Switch\:sides}$ (Not a required step)

$q+3\le \:15$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$q+3-3\le \:15-3\\=q\le \:12$

$\bold{q\le \:12}$

<u>Graphing</u>

5 0

2 years ago

Use the percent. proportion to solve 40% of what is 30?

AleksAgata [21]

Answer:

i belive its 75 percent

Step-by-step explanation:

the question is worded strangly

3 0

2 years ago