If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by div
1 answer:
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Answer:
x ≈ - 5.83 , x ≈ - 0.17
Step-by-step explanation:
x² + 6x + 1 = 0 ( subtract 1 from both sides )
x² + 6x = - 1
Using the method of completing the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(3)x + 9 = - 1 + 9
(x + 3)² = 8 ( take square root of both sides )
x + 3 = ± ( subtract 3 from both sides )
x = - 3 ±
Then
x = - 3 - ≈ - 5.83 ( to 2 dec. places )
x = - 3 + ≈ - 0.17 ( to 2 dec. places )
Answer:
Area of the walkway border is 736 ft²
Step-by-step explanation:
A rectangle is a quadrilateral (has four sides and four angles) with two pairs of opposite and parallel sides. All angles in a rectangle are 90 degrees each. Also, opposite sides are equal.
The entire pool area has a length of 60 feet and width of 40 feet. The area of the entire pool area is:
Area of entire pool = length * width = 60 feet * 40 feet = 2400 ft²
The area of entire pool
A walkaway border of 4 ft is made around the pool area. There is a decrease of 4 ft round the sides of the pool area.
Therefore length of pool = length of entire pool area - 4 feet border at left - 4 feet border at right = 60 ft - 4 ft - 4 ft = 52 ft
width of pool = width of entire pool area - 4 feet border at top - 4 feet border at bottom = 40 ft - 4 ft - 4 ft = 32 ft
Therefore the pool is 52 ft × 32 ft
Area of pool = length * width = 52 ft * 32 ft = 1664 ft²
Area of the walkway border = Entire pool area - Area of pool = 2400 ft² - 1664 ft² = 736 ft²
