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Veseljchak [2.6K]
3 years ago
14

If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by div

iding area by length? Simplify the answer.
Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0
Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / <span>8St^2
Rewriting the squared terms in simplified form :
</span>Width = 16 x S x S x t / <span>8 x S x t x t
</span>Cancelling the like terms
Width = 16 x S / <span>8 x t
</span>Cancelling the numeric terms :  

Width = 2S / <span>t</span>
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3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall
Katen [24]

Answer:

The volume of the toy is V=5.23\ ft^3

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

V=\frac{2}{3}\pi r^{3}

In this problem, the wide of the toy is equal to the diameter of the hemisphere

so

D=2\ ft

r=2/2=1\ ft ----> the radius is half the diameter

substitute

V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3

step 2

Find the volume of the cone

The volume of the cone is given by

V=\frac{1}{3}\pi r^{2}h

we know that

The radius of the cone is the same that the radius of the hemisphere

so

r=1\ ft

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

h=4-1=3\ ft

substitute the given values

V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

so

V=(\frac{2}{3} \pi+\pi)\ ft^3

V=(\frac{5}{3}\pi)\ ft^3

assume

\pi=3.14

V=\frac{5}{3}(3.14)=5.23\ ft^3

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3 years ago
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