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Veseljchak [2.6K]
3 years ago
14

If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by div

iding area by length? Simplify the answer.
Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0
Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / <span>8St^2
Rewriting the squared terms in simplified form :
</span>Width = 16 x S x S x t / <span>8 x S x t x t
</span>Cancelling the like terms
Width = 16 x S / <span>8 x t
</span>Cancelling the numeric terms :  

Width = 2S / <span>t</span>
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