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Tanzania [10]
3 years ago
7

Friends I want the answer for this . Can you give the answer ?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
8 0
The square number is 4 hence The answer is 4
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(3x - 15)° 0 + 25)<br> 105°<br> Find the value of a<br> Ox=35<br> O x 40<br> O x = 60<br> * = 65
timurjin [86]
X=40 degree is the correct answer
5 0
3 years ago
A customer buys bouquets of tulips and bouquets of roses for $.. What is the price of a bouquet of roses?
olchik [2.2K]

Question:

A customer buys bouquets of tulips and bouquets of roses for $40.25. The bouquet contained 17 tulips and cost $18.25. What is the price of a bouquet of roses?

Answer:

Rose =\$22.00

Step-by-step explanation:

Given

Total = \$40.25

Tulips = \$18.25

Required

The cost of a bouquet of roses

Since the customer bought a bouquet each, the formula to use is:

Total = Tulip + Rose

Make Rose the subject

Rose =Total - Tulip

Rose =\$40.25 - \$18.25

Rose =\$22.00

<em>A bouquet of rose costs $22.00</em>

7 0
2 years ago
What is the value of x when x/6 = 198?
docker41 [41]
Should be 1,188 , because 1,188 divided by six would be 198, hope I could help
3 0
3 years ago
25 POINTS
uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)


Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0
3 years ago
Read 2 more answers
Doris says 0 is not a rational number is she correct?
Sedaia [141]
As far as I know 0 IS a rational number. The only ones that are not rational are negative numbers. :) Though I could be wrong.....
7 0
3 years ago
Read 2 more answers
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