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3 years ago

________ symbol is used in the "Advanced" section of the time range picker to round down to nearest unit of specified time.

Computers and Technology

1 answer:

liberstina [14]3 years ago

8 0

Answer:

@(at sign) is the correct answer to the following statement.

Explanation:

Because the following symbol is the "at sign" symbol that is used for the Advanced section in the time range picker that lets the user search for the specified time for the round down the closest entity of a particular period. So, that's why the following answer is correct for the following statement.

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What is the difference between above ground mining and underground mining?

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If this is in reference to diamond mining then above ground would be panning while below ground would be the actual mining into the soil.

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3 years ago

Jasmine took many pictures at a photo shoot. She wants to transfer these pictures from her camera to her laptop for image enhanc

hoa [83]

The answer would more likely be A
If it’s not correct I’m very sorry

5 0

3 years ago

Guess the output #includes<stdio•h>

kondaur [170]

Hello. Is the one I work do.

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3 years ago

#include

rodikova [14]

Output

SORTED

4 7 10 69

SORTED

10 9 7 3

NOT SORTED

19 12 23 7

SORTED

5 5 5 5

Code

//The added part is in the bottom

#include <iostream>

using namespace std;

const int SIZE = 4;

bool isSorted (const int arr[], int size);

bool isNonDecreasing (const int arr[], int size);

bool isNonIncreasing (const int arr[], int size);

void printArr (const int arr[], int size);

int

main ()

{

int test1[] = { 4, 7, 10, 69 };

int test2[] = { 10, 9, 7, 3 };

int test3[] = { 19, 12, 23, 7 };

int test4[] = { 5, 5, 5, 5 };

if (!isSorted (test1, SIZE))

cout << "NOT ";

cout << "SORTED" << endl;

printArr (test1, SIZE);

if (!isSorted (test2, SIZE))

cout << "NOT ";

cout << "SORTED" << endl;

printArr (test2, SIZE);

if (!isSorted (test3, SIZE))

cout << "NOT ";

cout << "SORTED" << endl;

printArr (test3, SIZE);

if (!isSorted (test4, SIZE))

cout << "NOT ";

cout << "SORTED" << endl;

printArr (test4, SIZE);

return 0;

}

bool

isSorted (const int arr[], int size)

{

//Added part

if (isNonDecreasing (arr, size) || isNonIncreasing (arr, size))

{

return true;

}

else

{

return false;

}

bool

isNonDecreasing (const int arr[], int size)

{

for (int i = 0; i < (size - 1); i++)

{

if (arr[i] > arr[i + 1]) //It compares the n value with the n-1 value and output

{

return false;

break;

}

return true;

}

bool

isNonIncreasing (const int arr[], int size)

{

for (int i = 0; i < (size - 1); i++)

{

if (arr[i] < arr[i + 1]) //It compares the n value with the n-1 value and output reautilization of previous function by replacing only “<”

{

return false;

break;

}

return true;

}

void

printArr (const int arr[], int size)

{

for (int i = 0; i < size; i++)

cout << arr[i] << " ";

cout << endl << endl;

}

7 0

3 years ago

Assign a pointer to any instance of searchChar in personName to searchResult.#include #include using namespace std;int main() {c

Firlakuza [10]

Answer:

Here it the solution statement:

searchResult = strchr(personName, searchChar);

This statement uses strchr function which is used to find the occurrence of a character (searchChar) in a string (personName). The result is assigned to searchResult.

Headerfile cstring is included in order to use this method.

Explanation:

Here is the complete program

#include<iostream> //to use input output functions

#include <cstring> //to use strchr function

using namespace std; //to access objects like cin cout

int main() { // start of main() function body

char personName[100]; //char type array that holds person name

char searchChar; //stores character to be searched in personName

char* searchResult = nullptr; // pointer. This statement is same as searchResult = NULL

cin.getline(personName, 100); //reads the input string i.e. person name

cin >> searchChar; // reads the value of searchChar which is the character to be searched in personNa,e

/* Your solution goes here */

searchResult = strchr(personName, searchChar); //find the first occurrence of a searchChar in personName

if (searchResult != nullptr) //if searchResult is not equal to nullptr

{cout << "Character found." << endl;} //displays character found

else //if searchResult is equal to null

{cout << "Character not found." << endl;} // displays Character not found

return 0;}

For example the user enters the following string as personName

Albert Johnson

and user enters the searchChar as:

Then the strchr() searches the first occurrence of J in AlbertJohnson.

The above program gives the following output:

Character found.

8 0

3 years ago