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ololo11 [35]
3 years ago
8

If there is a circuit that is being used 36 CCS then how much of that circuit is being used in Erlang?

Computers and Technology
1 answer:
Mkey [24]3 years ago
5 0

Answer:

A.1.

Explanation:

CCS(Centum Call Seconds) is a unit to measure the network traffic in the telecommunication circuit network.        

1 Traffic unit = 1 Erlang.      

The relation between Erlang and CCS(Centum Call Seconds) is:-

36 CCS = 1 Erlang.          

Hence the answer to this question is 1 Erlang.

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3 years ago
Consider the formula: G=D+(A+C^2)*E/(D+B)^3 Show the order that a processor would follow to calculate G. To do so, break down th
motikmotik

Answer:

1. G=D+(A+C^2)*E/(D+B)^3

cobegin:

p1: (D+B)

p2: p1^3

p3: C^2

p4: A+ p3

p5: E/p2

p6: p4 * p5

p7: D + p6

   :G

coend

2. Now The value A=2, B=4, C=5, D=6, and E=8

p1: 6+4 =10

p2: p1 ^3= 10^3= 1000

p3: c^2= 5^2 =25

p4: A + p3= 2 +25 =27

p5: 8/1000

p6: 27 *8/1000

p7: D+ P6= 6+ 216/1000

      = 6216/1000

      =6.216

Explanation:

The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.

4 0
2 years ago
Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
daser333 [38]

Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

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 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

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 }

}

 

/**

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 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

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     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

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      System.exit(0);

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public void largerArray(){

 Object[] other = new Object[this.array.length*2];

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}

 

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 * @return true if there are null elements

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public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

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}

 

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public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

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   continue;

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   string += this.array[i]+", ";

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 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

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/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

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public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

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   else{

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   if(this.array[i] == object.array[i])

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6 0
2 years ago
3 features of digital computer​
jolli1 [7]

Answer:

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Explanation:

6 0
2 years ago
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zepelin [54]

Answer:

d) daco = new Banana;

Explanation:

Dynamically allocated variables have their memory allocated in the heap memory.We declare a dynamical variable like this:-

int *a=new int ;

It means a pointer a is created on the stack memory which hold the address of the block that hold the value of variable a in heap memory.

We already have the pointer daco. We just have to initialize with keyword new.

It will be like daco=new Banana; which matches the option d.

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3 years ago
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