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Alecsey [184]
2 years ago
5

What type of hacker is primarily motivated by an ideology, epitomizing "the ends justify the means" mentality?.

Computers and Technology
1 answer:
Hunter-Best [27]2 years ago
5 0

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism.

<h3>What type of hackers are motivated by social or political issues?</h3>

Hacktivism is known to be an act of the wrong use a computer system or network for a socially or politically motivated  aim or reason.

The type of hacker that is primarily moved by an ideology, epitomizing "the ends justify the means" mentality is Hacktivism and they are called hacktivist.

Learn more about Hacktivism from

brainly.com/question/5483494

#SPJ1

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What is the initial condition in this set of code?
marissa [1.9K]

Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.

The video above uses the example

{

d

y

d

x

=

cos

(

x

)

y

(

0

)

=

−

1

to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you  

y

=

sin

(

x

)

+

C

.

Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in  

0

for  

x

and  

−

1

for  

y

gives us  

−

1

=

C

, meaning that the particular solution must be  

y

=

sin

(

x

)

−

1

.

So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.

Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be  

y

-values. Higher-order equations might have an initial value for both  

y

and  

y

′

, for example.

Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.

Explanation:

5 0
2 years ago
Which of the following statements are true?
grin007 [14]

Answer:

I think the answer are two which are B and C

7 0
3 years ago
This is your code.
lubasha [3.4K]

Answer:

35

Explanation:

We will be going inside B array, because he was in second place in array E,and will be the first element of array B, so it's 35

E can be understanded as:

E=[[21, 'dog', 'red'],[35, 'cat', 'blue'],[12, 'fish', 'green']], so, you can see array E as array of arrays or so-called two-dimensional array

6 0
2 years ago
In which file format is image data compiled into a binary file? TIFF SVG CGM BMP
Licemer1 [7]

BMP (Bitmap). I may be wrong. I'm sorry.

6 0
3 years ago
Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use
jeyben [28]

Question:

Define a function compute_gas_volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the gas equation PV = nRT, where P is pressure in Pascals, V is volume in cubic meters, n is number of moles, R is the gas constant 8.3144621 ( J / (mol*K)), and T is temperature in Kelvin.

Answer:

This solution is implemented in C++

double compute_gas_volume(double P, double T, double n){

   double V = 8.3144621 * n * T/P;

   return V;

}

Explanation:

This line defines the function, along with three parameters

double compute_gas_volume(double P, double T, double n){

This calculates the volume

   double V = 8.3144621 * n * T/P;

This returns the calculated volume

   return V;

}

To call the function  from the main, use:

<em>cout<<compute_gas_volume(P,T,n);</em>

<em />

<em>Where P, T and n are double variables and they must have been initialized</em>

5 0
3 years ago
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