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Radda [10]
3 years ago
10

Eeva spent 5/6 of her total allowance on a hair crimpler. What fraction of her total allowance did Eeva have left

Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

1/6

Step-by-step explanation:

6/6 is one whole, so subtract what she spent, which is 5/6. Leaving us with 1/6

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Mike wants to fence in part of his backyard. He wants the length of the fenced-in area to be at least 20 feet long, l ≥ 20. He h
zhuklara [117]

I added a screenshot of the complete question along with the given choices.

<em><u>Answers:</u></em>

w = 10 ft and l = 50 ft ................> second option

w = 20 ft and l = 60 ft ...............> third option

w = 50 ft and l = 40 ft ...............> fifth option

<em><u>Explanation:</u></em>

<u>We are given that:</u>

length should be at least 20 ...........> length ≥ 20

equation for perimeter is : 2l + 2w ≤ 200

<u>We will check each option as follows:</u>

<u>Option 1:</u>

w = 50 ft and l = 10 ft

This option is incorrect as the proposed length is less than 20.

<u>Option 2:</u>

w = 10 ft and l = 50 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(10) = 100 + 20 = 120 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 3:</u>

w = 20 ft and l = 60 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(60) + 2(20) = 120 + 40 = 160 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 4:</u>

w = 90 ft and l = 30 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(30) + 2(90) = 60 + 180 = 240 > 200

The second condition is not satisfied.

This option is incorrect

<u>Option 5:</u>

w = 50 ft and l = 40 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(40) = 100 + 80 = 180 ≤ 200

The second condition is also satisfied.

This option is correct

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Question is in the picture<br>please help
LiRa [457]

When given the graph of a function, the domain would include all the points that there is a graph. The strategy is to find what <em>is not</em> included.

What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

At x = 4 there is an unfilled (or open) circle and that means we exclude 4.

At x = 5 there is a filled circle so we include 5.

Now we refine our domain for the endpoints.

x ≤ -3, -1 < x < 4, x ≥ 5 is our domain.

The problem gives us intervals, and we gave it in inequalities. When we include an endpoint we use brackets - [ and } and when we exclude and endpoint we use parentheses - ( and ). Let's go back to x ≤ -3. Anything less works, and -3 is included (closed circle). That interval is (-∞, -3]. Next is the piece between -1 and 4. Since both are excluded, (-1,4) is our interval. We include 5 to write x ≥5 as the interval [5,∞).

Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

5 0
3 years ago
In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen
fenix001 [56]
Let
 x = number of common cars
 y = number of suvs
 we can write the following system of equations
 x-y = 12
 x = 1.429y
 Solving the system we have
 x-y = 12
 1.429y-y = 12
 and (1,429-1) = 12
 y = (12) / (1,429-1) = 27.97202797
 then,
 x = 1429 * (27.97202797)
 x = 39.97202797
 answer
 The number of suvs in the parking lot is 28
6 0
3 years ago
GIVING BRAINLIEST Graph the equation y=2x−5.
sergiy2304 [10]

Answer: y=−10

Step-by-step explanation: GIVE ME BRAINLIEST HOPE THAT HELPED

8 0
2 years ago
Coco's garden has 888 tomato plants, 444 pepper plants, 333 squash plants, and 666 pumpkin plants.
AveGali [126]
888 + 444 + 333 + 666 = 2331 / 7 = 3

3 * 222 = 666

There are 666 of the plants 

I hope this helps :)
6 0
3 years ago
Read 2 more answers
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