Answer:
(D)
Step-by-step explanation:
The box plot is a visual representation of the 5-number summary of the data. It shows the extremes, the quartiles and the median.
__
Each data set has 11 elements, sorted into increasing order.
<h3>extremes</h3>
The first and last elements of the data set correspond to the ends of the whiskers, so you are looking for a set that ranges from 3 to 18. (This eliminates choice B.)
<h3>median</h3>
The median will be the middle element, the 6th from either end. The vertical line in the box identifies its value as 10. (This eliminates choice A.)
<h3>quartiles</h3>
The first quartile is the middle element of the bottom half of the data set (what remains after the median and above elements are removed). There are 5 elements in the bottom half, so the first quartile is the 3rd one. It is signified by the left end of the box in the box plot. Its value is 7. (This eliminates choice C.)
Similarly, the third quartile is the 3rd element from the right end of the data set. The value 13 in choice D matches the right end of the box in the box plot.
The box plot represents the data set in Choice D.
Answer:
c
Step-by-step explanation:
im not for sure but i think its c
The <u>probability</u> that a point <u>chosen at random</u> in the triangle is also in the blue square can be calculated using <u>geometrical definition of the probability</u>:

1. Find the total area of the triangle:

2. Find the desired area of the square:

Then the probability is

Answer: correct choice is B
Answer:
b must equal 7 and a second solution to the system must be located at (2, 5).
Step-by-step explanation:
Rearranging the first equation:
y = (x - 3)^2 + 4
From this we see that the vertex is at the point (3,4).
So one solution of equation 2 is (3 ,4).
Substituting in equation 2:
4 = -3 + b
b = 7.
So equation 2 is y = - x + 7.
Now we check if (2, 5) is on this line:
5 = -2 + 7 = 5 , therefore (2, 5) is on this line.
Verifying if (2, 5) is also on y = (x - 3)^2 + 4:
5 = (2 - 3)^2 + 4 = 1 + 4 = 5
- so it is. and a second solution to the system is (2, 5).