Question

A roadside vegetable stand sells pumpkins for $5 each and squashes for $3 each. One day they sold 6 more squash than pumpkins and their sales totaled $98. Write and solve a system of equations to find how many pumpkins and squash they sold

Answer 1

$x-\ pumpkins\\ y-\ squashes\\\\ y=x+6\\ 3y+5x=98\\\\3(x+6)+5x=98\\ 3x+18+5x=98\\ 8x+18=98\ \ | subtract\ 18\\ 8x=80\ \ | divide\ by\ 8\\ x=10\\ y=10+6=16\\\\ They\ sold \ 10\ pumpkins\ and\ 16\ squashes.$