Where is the hole for the following function located?

1 answer:

7 0

It would seem to be a good idea to cancel the (x + 3) factors to get f(x) = 1/(x - 4)
This is a hyperbolic graph with a vertical asymptote at x = 4.
However when x = -3 the factor (x + 3) = 0 so cannot be cancelled at this point. 0/0 is undefined.
The graph is drawn leaving a hole in the line at x = -3
The limits as we approach x = -3 from above or below that point get closer and closer to -1/7

The correct answer is A

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