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3 years ago

Simplify. 1/4+4(1/2−3/4)^2

Mathematics

1 answer:

ohaa [14]3 years ago

4 0

Hope this helps. If you have any further question, ask in comments.

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For Triangle PQM, where M is the Right Angle and PQ is the Hypotenuse. You know side PM = 8, side PQ = 17, Side MQ = 15. Find An

Sergeeva-Olga [200]

Answer:

61.9°

Step-by-step explanation:

tan p = opposite/ adjacent

tan p = 15/8

$tan^{-1}$ (15/8)

4 0

3 years ago

Find f(-10) f(x)=7x-5

Inessa [10]

Answer:

Step-by-step explanation:

F(x) is simply another way of saying y. We are given the x value of -10. We can substitute this in for x and find y.

f(-10) = 7(-10) - 5

f(-10) = -70 - 5

f(-10) = -75

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3 years ago

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HELP FOR 15 POINTS!The table shows the number of minutes in different numbers of days.

GalinKa [24]

B is the right answer m=1440d

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4 years ago

Read 2 more answers

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

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Explanation:

We have a triangle with these side lengths:

a = 10
b = 16
c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need $b^2 < a^2+c^2$ to be true in order for an acute triangle to happen.

So,

$b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5$

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

$c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\$

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0

3 years ago

Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov

Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

Total days taken to cover entire bread are 8

Let Area of bread be A

So Area covered (A) corresponds to 8 days with doubling.

So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

So on 5ht day =A(6)/2 ,4th= A(5)/2, on 3rd= A(4)/2, on 2nd=A(3)/2

On 1st =A(2)/2

So we required Area= half of total.

<em>One day before the 8th day will be 7th day</em>

<em>on that day it will cover half are so that on next day will cover the double of the previous area consumed.</em>

4 0

3 years ago