Answer:
The first step is calculate the degrees of freedom, on this case:
Since is a one side test the p value would be:
And the best option for this case would be:
None of the above (it should be t(38) = 5.07, p < .01)
Step-by-step explanation:
Data given and notation
represent the mean for the sample 1
represent the mean for the sample 2
represent the sample standard deviation for the sample 1
represent the sample standard deviation for the sample 2
sample size selected for 1
sample size selected for 2
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean for the group 1 is higher than the mean for group 2, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one side test the p value would be:
And the best option for this case would be:
None of the above (it should be t(38) = 5.07, p < .01)