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Zina [86]
3 years ago
10

Simplify. Rewrite the expression in the form a^n. A • A^7

Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0
<h2>Product of Powers Rule</h2><h3>Answer:</h3>

A^8

<h3 />

Step-by-step explanation:

Recall the Exponent Law:

a^m \cdot a^n = a^{m +n}

This means that if you multiply numbers with exponents and they have the same bases such as, a, the result is the number raised to the sum of exponents.

Solution:

Note: All numbers implicitly have 1 as their exponent. For example, 8 is equivalent to 8^1.

A \cdot A^7 \\ A^{1 +7} \\ A^8

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Help quick please
GaryK [48]

Answer:

Growth

Step-by-step explanation:

since the (1.05) is bigger than 1 it is growth but if it was lower then  1 it would be decay .

3 0
3 years ago
I know its easy but i suck at math pls help
e-lub [12.9K]

Answer:

-6.8125

Step-by-step explanation:

Convert 13/16 to a decimal.

Write -6 down

You get -6.8125.

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4 years ago
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150 students were surveyed on how many text messages to send in a date for different devices. let X represent the number of stud
kakasveta [241]

Given that the total number of students that sent messages = 150 students

a) To obtain the equation to represent the number of students who send text messages, we will sum up the variables in the Venn diagram and equate it to 150.

\begin{gathered} 75+x+3x+x=150 \\ x+3x+x=150-75 \\ 5x=75 \end{gathered}

Hence, the equation is

5x=75

b) Solving for x

\begin{gathered} 5x=75 \\ x=\frac{75}{5}=15 \\ \therefore x=15 \end{gathered}

Therefore, x = 15.

c) The total number of student that uses cell phone = 75 + x = 75 + 15= 90students

The total number of students that sent messages = 150students

The formula for probability is,

\text{Probability = }\frac{\text{Number of students that uses cell phone}}{\text{Total number of students}}

Hence,

P(\text{Number of students that uses cell phone)}=\frac{90}{150}=\frac{3}{5}

Therefore, the probability that a randomly chosen student uses their cell phone to send text messages ​is 3/5.

7 0
1 year ago
A population has a known standard deviation of 1.27 and a sample space contains 85 values find the margin of error needed to cre
r-ruslan [8.4K]

Answer:

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 1.27, n = 85

So

M = z*\frac{\sigma}{\sqrt{n}}

M = 2.575*\frac{1.27}{\sqrt{85}}

M = 0.3547

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

7 0
4 years ago
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