Two and one thirds will be located between 2 and 3.
hope this helps :)
Answer:
a) -13.9 ft/s
b) 13.9 ft/s
Step-by-step explanation:
a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:
(1)

(2)
Since:

When x = 45 (the batter is halfway to first base), D is:

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.
b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

(3)
We have that D is:

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.
I hope it helps you!
Answer:
[1] x - 6y = 3
[2] x + 2y = 5
Graphic Representation of the Equations :
-6y + x = 3 2y + x = 5
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -2y + 5
// Plug this in for variable x in equation [1]
[1] (-2y+5) - 6y = 3
[1] - 8y = -2
// Solve equation [1] for the variable y
[1] 8y = 2
[1] y = 1/4
// By now we know this much :
x = -2y+5
y = 1/4
// Use the y value to solve for x
x = -2(1/4)+5 = 9/2
Solution :
{x,y} = {9/2,1/4}
You have to use factors of 15 are 3 and 5