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4 years ago

10

Integral of arctan(8x) dx.

1 answer:

vaieri [72.5K]4 years ago

5 0

<span>we are asked to determine the integral tan^(-1)(8 x) dx. we use the inverse property of trigonometric equation in integral calculus such that the answer is </span><span>integral tan^(-1)(8 x) dx. = </span>x tan^(-1)(8 x)-1/16 log(64 x^2+1)+ C where C is a constant.

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