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nikitadnepr [17]

2 years ago

12

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end

{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 6x+5y=1 6x−5y=7 Choose all answers that apply: Choose all answers that apply: (Choice A) A Add the equations. (Choice B) B Subtract the bottom equation from the top equation. (Choice C) C Multiply the top equation by 777, then subtract the bottom equation from the top equation.

1 answer:

frez [133]2 years ago

5 0

Answer:

Option A and B are correct

Step-by-step explanation:

We have to add here

6x+5y=1.

6x-5y=7

sow e will get 12x=8 , x=8/12=2/3

Option A is correct.

If We substract bottom from furst then

6x+5y=1

-6x+5y=-7

10y=-6

y=-6/10=-3/5

we put y=-3/5 in any equation and find x

6x+5(-3/5)=1

6x=4

x=4/6=2/3

So Option B also correct.

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The sum of a number and forty-six

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$\bullet \ \textsf{The word \bf{\underline{SUM}}}\textsf{\ means\ add/addition}}$

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$\bullet\textsf{ \underline{forty-six} is 46}$

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$- \ \textsf{We can say that x is on your left}$

$-\ \textsf{ + can be in your middle}$

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4 0

2 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

F(-4,5), G(3,3), H(6,-4) and I(-1,-2).

lisabon 2012 [21]

I didn't mean to post the answer and can't figure out how to take it down. Somebody report it so it does go down and the question can be later answered. Thank you

4 0

2 years ago

Write your question here keep it simple and clear

igor_vitrenko [27]

｡☆✼★ ━━━━━━━━━━━━━━ ☾

12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

Have A Nice Day ❤

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7 0

2 years ago

Please help me......................................

Irina18 [472]

Answer:

148.5

Step-by-step explanation:

times all

3 0

2 years ago