y = 90°
Solution:
The reference image for the answer is attached below.
The sum of opposite interior angles is equal to the exterior angles.
m∠BAC + m∠ACB = 110°
m∠BAC + 70° = 110°
m∠BAC = 110° – 70°
m∠BAC = 40°
m∠BAD + m∠DAC = 40°
x + x = 40°
2x = 40°
Divide by 2 on both sides of the equation.
x = 20°
In triangle DAC,
Sum of all the angles of a triangle = 180°
m∠DAC + m∠ACD + m∠CDA = 180°
20° + 70° + m∠CDA = 180°
90° + m∠CDA = 180°
m∠CDA = 180° – 90°
m∠CDA = 90°
∠CDA and y lies on the straight line. So they form a linear pair.
y + m∠CDA = 180°
y + 90° = 180°
y = 180° – 90°
y = 90°
The value of y is 90°.
Answer:
(A) - (5)
(B) - (4)
(C) - (1)
(D) - (2)
Step-by-step explanation:
(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]
(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.
(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).
(4) The related polynomial equation has a total of six roots; two roots are complex and one of the remaining real roots has a multiplicity of 3.
(C) We are given the polynomial (x+3)(x−5)(x+2)²
(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.
(D) We are given the polynomial (x+2)²(x+1)²
(2) The related polynomial equation has a total four roots; all four roots are real and two roots have a multiplicity of 2. (Answer)
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