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luda_lava [24]
3 years ago
6

What is 1 over 10 as a percentage?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0
It's 10%! ;3 (I think.)
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Look at the graph of f(x)=x^2+6x+10. What is the average rate of change between {1,3}?
nydimaria [60]
This equals [f(3) - f(1)]  / [3-1]

=  3^2 + 6(3) + 10 - (1^2 + 6(1) + 10)  / 2

=   (37 - 17) / 2

= 10 Answer
3 0
3 years ago
Anyone know the answer??
Xelga [282]

Answer

3.5 x 10^{3}

Step-by-step explanation

3 0
3 years ago
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
How to find the radius of a circle when given two points?
enyata [817]
With the diameter..
4 0
3 years ago
Read 2 more answers
What is the answer for -12+x/11=-3
dem82 [27]

Answer:

x = 99

Step-by-step explanation:

<u>Step 1:  Solve for x</u>

-12 + x/11 + 12 = -3 + 12

x/11 * 11 = 9 * 11

x = 99

Answer:  x = 99

3 0
3 years ago
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