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3 years ago

#freepoints 100 POINTS TO WHOEVER NAMES THEIRSELVES REETARJO REEKARDO

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

Reetarjo reekardo

Step-by-step explanation:

Pachacha [2.7K]3 years ago

3 0

Step-by-step explanation:

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Urgent!!!!! please help

Anastaziya [24]

Answer:

Step-by-step explanation:

I will edit and add my explanation

The 3 and 2 are both positive if the information that was given in the screenshot is standalone.

So if the numerals are both positive, they must be traveling to the right because the number line is increasing towards the right.

We can narrow the choices down to A and C because they both move right.

Since neither of the numbers are negative, it must start from the center 0 and increase, so it must be A.

3 * 2 is also 6, so it must end on 6.

7 0

3 years ago

Which of the following best shows how the internet affects the economic

weqwewe [10]

Answer:The answer is B. I just did it. good luck!

Step-by-step explanation:

6 0

3 years ago

The Fall Festival charges $0.75 per ticket for the rides. Kendall bought 18 tickets for rides and spent a total of $33.50 at the

PIT_PIT [208]

Tickets cost $0.75t. Kendall bought 18 tickets, so you can substitute 18 for the variable t because it stands for the amount of tickets bought.

$0.75(18) = $13.50

Kendall spent a total of $33.50, so that means she spent $13.50 on tickets and the rest she spent on admission, so 33.50 - 13.50 = 20; she spent $20.00 on admission.

(a) The variable are t, amount of tickets bought, and a, admission price.

(b) The linear equation for anyone who only pays for festival admission and rides would look like: 0.75t + a.

(c) I made the linear equation 0.75t + a because first you would have to pay the admission fee (a), and then you would pay for EACH ticket (t). So t would be the changing variable depending on how many tickets a person would choose to buy.

3 0

3 years ago

A national survey of 2000 adult citizens of a nation found that 24% dreaded Valentine's Day. The margin of error for the surve

Goryan [66]

Answer:

The correct option is (A).

Step-by-step explanation:

The (1 - α)% confidence interval for the population proportion is:

$CI=\hat p \pm MOE$

The information provided is:

$\hat p$ = 0.24

MOE = 0.089

The 85% confidence interval for the population proportion of adults who dreaded Valentine's Day is:

$CI=\hat p \pm MOE$

$=0.24\pm 0.089\\=(0.151, 0.329)$

So, the 85% confidence interval for the population proportion of adults who dreaded Valentine's Day is (0.151, 0.329).

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

So, the 85% confidence interval for the population proportion, (0.151, 0.329), implies that there is 85% confidence that the proportion of the adult citizens of the nation that dreaded Valentine's Day is between 0.151 and 0.329.

Or there is 0.85 probability that the true proportion of the adult citizens of the nation that dreaded Valentine's Day is between 0.151 and 0.329.

Thus, the correct option is (A).

7 0

3 years ago

connor. counted twice as many zebras as clowns in the carnival.he counted a total of 36clowns and zebras in all.how many zebras

olga nikolaevna [1]

36 clowns and zebras..
if there are twice as many zebras as clowns then divide the amount by 2
36/2 = 18 so..
now there are 18 zebras and 18 clowns but we want twice as many zebras..

so by process of elimination we can figure out that
there are 24 zebras and 12 clowns which = 36
the answer is 24 zebras Connor counted

5 0

3 years ago