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3 years ago

What key would you use is 10 students chose cartoons

1 answer:

8 0

<span>1.Colour 2.size 3.labelling 4.speech bubbles 5.symbols 6.focus 7.angle 8.tone 9.Facial expressions 10.context these are the t key would you use is 10 students chose cartoons</span>

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Convert the following polar-form vectors of the form ⟨r,θ⟩ into component-form vectors of the form ⟨x,y⟩. Your answers should be

storchak [24]

9514 1404 393

Answer:

a) <8.356, 9.959>

b) <-0.605, -1.663>

c) <-5.023, 2.9>

Step-by-step explanation:

Many calculators can perform polar ⇔ rectangular conversion. Attached is the result from one of them. Of course, you can also program a spreadsheet to do it. (The ATAN2( ) function is useful for finding the correct angle.)

If you want to do these calculations by hand, the conversion is ...

<r, θ> ⇒ <r·cos(θ), r·sin(θ)>

In the attached, the rectangular coordinates are shown as complex numbers. The imaginary component is the y-component of the vector.

8 0

3 years ago

What is the slope of a ladder leaning against the wall? (10 ft, 9ft, 3ft)

allsm [11]

the ladder leaning against the wall has slope 3

7 0

3 years ago

Evaluate 8^<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D" id="TexFormula1" title="\frac{5}{3}" alt="\frac{5}{3}" align

almond37 [142]

Answer:

Step-by-step explanation:

32 is the correct answer

6 0

3 years ago

Read 2 more answers

You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)

Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, $v_1$ = = 20 m./s

Velocity of the truck 2, $v_2$ = 35 m./s

1. Kinetic energy of the truck 1: $\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules$

Kinetic energy of the truck 2: $\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules$

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = $mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules$

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0

4 years ago

Find the slope and reduce of p=(3/4,1 1/4) q=(-1/2,-1)

sergij07 [2.7K]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
p&({{ \frac{3}{4}}}\quad ,&{{ \frac{1}{4}}})\quad 
% (c,d)
q&({{ -\frac{1}{2}}}\quad ,&{{ -1}})
\end{array}$

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-\frac{1}{4}}{-\frac{1}{2}-\frac{3}{4}}\quad \cfrac{\leftarrow LCD=4}{\leftarrow LCD=4}
\\\\\\
\cfrac{\frac{-4-1}{4}}{\frac{-2\cdot 1-3}{4}}\implies \cfrac{\frac{-5}{4}}{\frac{-5}{4}}\implies \cfrac{-5}{4}\cdot \cfrac{4}{-5}\implies 1$

7 0

3 years ago