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ankoles [38]
2 years ago
11

Evaluate 8^

="absmiddle" class="latex-formula">
Mathematics
2 answers:
Minchanka [31]2 years ago
7 0
8^5/3 = 10922.666666 (repeating)
almond37 [142]2 years ago
6 0

Answer:

Step-by-step explanation:

32 is the correct answer

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Which binomial is a factor of the expression?<br><br><br>Zoom in to see clearer :)​
sweet [91]

Answer:

x + 3 is the factor of given expression !!!

Step-by-step explanation:

here's the solution in attachment.

8 0
3 years ago
Please answer today or tomorrow. The outside temperature was 5 degrees Fahrenheit. How many degrees below the freezing point of
Arada [10]

Answer:

water freezes in 32 degrees

so 32-5=27

so it was 27 degrees bellow the freezjng point of water

5 0
2 years ago
Find length and width .the lenght is 10 times as long as the width.P=308
patriot [66]

<span>Width(height): x
length of rectangle: 10x 
perimeter: width +width +length +length = 308 inches
or ------- 2width+2length=308
2x+2(10x)=308
2x+20x=308
22x=308</span>

<span>
x=14 the width is 14 inches 
length:
10x
10*14
140 inches 
ANSWER: 
Length:140 inches
Width: 14 inches</span>

8 0
3 years ago
Find the distance between the point (3, 5) and a line with the equation 5 x - 3 y + 10 = 0
timama [110]

The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.

<h3>What is the distance between a point and a line?</h3>

Let (x₁, y₁) be the point and ax + by + c = 0 be the line.

Then the distance between a point and a line will be

\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}

The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.

Then the distance between them will be

\rm d = \dfrac{|5 *3 - 3 *5 + 10|}{\sqrt{5^2 + (-3)^2}}\\d = \dfrac{10 }{\sqrt{34}} \ units

Learn more about the distance between a point and a line here;

brainly.com/question/11558698

#SPJ1

7 0
2 years ago
Which expression has a product of 32.76 and why?
Anuta_ua [19.1K]

Answer:

20.00+12.76 would give you that sum

Step-by-step explanation:

5 0
2 years ago
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