The value for n is 
<h3>solving for n</h3>
<u>given data</u>
10n^{2} - 12 = -8
making n the subject of the formula
10n^{2} = -8 + 12
10n^{2} = 4
divide through by 10
n^{2} = 4 / 10
finding the square root of both sides
n = square root ( 4 / 10 )

n = 0.632 or 
Read more the subject of formula here: brainly.com/question/21140562
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Your answer is going to be letter D.)?
Answer:
+120/169 or -120/169
Step-by-step explanation:
- let
![cos^{-1}[\frac{5}{13} ] = \alpha](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%5B%5Cfrac%7B5%7D%7B13%7D%20%20%5D%20%3D%20%5Calpha)
where, alpha is some angle that satisfies the assumed condition.
- so,

[ taking cos to the other side or applying cos on both sides]
- now, substitute this in the given expression
as sin
= 
[by general trigonometry formula:
]
so if
, we can get sin
from the above formula as + or - 12/13
(because, after taking square root on both sides we keep + or -]
- as, sin
![2\beta = 2*sin[\beta ]*cos[\beta ]](https://tex.z-dn.net/?f=2%5Cbeta%20%20%3D%202%2Asin%5B%5Cbeta%20%5D%2Acos%5B%5Cbeta%20%5D)
[by general trigonometry formula]
- here, now
![sin[2\alpha ]=2*(+or- 12/13)*5/13\\](https://tex.z-dn.net/?f=sin%5B2%5Calpha%20%5D%3D2%2A%28%2Bor-%2012%2F13%29%2A5%2F13%5C%5C)
so, the final value can be 120/169 or -120/169.
Answer:
2k + 4 > k + 11
Step-by-step explanation:
Keywords:
more - addition
twice - multiplication
greater than - >
sum - addition
4 more than twice the number k
2k + 4
Greater than
>
Sum of k and 11
k + 11
2k + 4 > k + 11
Solve for k if needed.
2k + 4 > k + 11
2k > k + 7
k > 7
Best of Luck!