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vichka [17]
3 years ago
6

The bids in an online auction are represented by the arithmetic sequence shown below: right on explicit formula to represent the

bids as an arithmetic sequence. What is the tenth bid

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

10th bid is 292

Step-by-step explanation:

Here, as we can see, we have an arithmetic sequence and we want to calculate its 10th term

From the question, we can see that the first term a is 193

The common difference is 204-193 = 11

The formula for the nth term of a sequence is;

a + (n-1)d

In this case, n = 10

so we have ;

193 + (10-1)11

= 193 + 99 = 292

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Samuel is running a 3-mile race. He would like to finish the race in under 33 minutes. He has already run for 10.5 minutes. The
Y_Kistochka [10]
For this case we have the following inequality:
 10.5 + x \ \textless \ 33

 From here, we define the variable x.
 x: number of minutes remaining to finish the race.
 From here, we clear the value of x.
 We have then:
 x \ \textless \ 33-10.5

 x \ \textless \ 22.5

 Therefore, Samuel has less than 22.5 minutes to finish the race in the estimated time.
 Answer:
 
x < 22.5; Sam has fewer than 22.5 minutes left to finish running.
7 0
3 years ago
Read 2 more answers
you accidentally dropped a coin from the top of 10 stairs. what is the probability that it will land on the 4th step facing up
Roman55 [17]

Answer:

Step-by-step explanation:

1/10 * 1/4 = 1/14

1/2 because there is a 50/50% chance its either heads or tails

3 0
4 years ago
Please help me Thanks &lt;3
Gnom [1K]
The answer is number two since in y=Mx+c, C is the y intercept. This means that 52 is the y intercept. Therefore, Jordan is charged $52 for each gigabyte of data she uses.
8 0
3 years ago
The waiting times on hold for a call to a customer service department are observed to have the following probability distributio
Elina [12.6K]

Answer:

b. 9.2 minutes

Step-by-step explanation:

To find the expected waiting time for a random call from the sampie given by using the formula:

\sum (f(X)) = \dfrac{\sum f (x) \times x}{\sum x}

number of calls (x)           waiting time f(x) in minutes         f(x) *(x)

0                                                     0                                         0            

2                                                     3                                         6

4                                                     10                                       40

6                                                     15                                       90  

8                                                     10                                       80

10                                                     6                                       60  

\sum x = 30                                                                          \sum f(x) *x = 276

Therefore:

\sum (f(X)) = \dfrac{276}{30}

\sum (f(X)) = 9.2

5 0
3 years ago
If f(x) = 2x2 + 3x and g(x) = x – 2, what is (f +
LUCKY_DIMON [66]
F(x) = 2x²+3x
g(x)= x-2

f(x)+ g(x) =( 2x²+3x ) +(x-2)
= 2x²+3x+x-2
= 2x²+4x-2

(f+g)(2) = 2(2)²+4(2)-2
= 2•4+8-2
= 8+8-2
= 14



hope to helped
4 0
4 years ago
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