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vichka [17]
3 years ago
6

The bids in an online auction are represented by the arithmetic sequence shown below: right on explicit formula to represent the

bids as an arithmetic sequence. What is the tenth bid

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

10th bid is 292

Step-by-step explanation:

Here, as we can see, we have an arithmetic sequence and we want to calculate its 10th term

From the question, we can see that the first term a is 193

The common difference is 204-193 = 11

The formula for the nth term of a sequence is;

a + (n-1)d

In this case, n = 10

so we have ;

193 + (10-1)11

= 193 + 99 = 292

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10n^{2} - 12 = -8<br> Please help
torisob [31]

The value for n is \frac{\sqrt{10} }{5}

<h3>solving for n</h3>

<u>given data</u>

10n^{2} - 12 = -8

making n the subject of the formula

10n^{2}  = -8 + 12

10n^{2}  = 4

divide through by 10

n^{2}  = 4 / 10

finding the square root of both sides

n = square root ( 4 / 10 )

n = \sqrt{\frac{4}{10}

n = 0.632 or \frac{\sqrt{10} }{5}

Read more the subject of formula here: brainly.com/question/21140562

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7 0
2 years ago
Which pair of triangles are congruent by ASA ?
Eddi Din [679]
Your answer is going to be letter D.)?
6 0
3 years ago
Question is in the picture pls help.
Usimov [2.4K]

Answer:

c. is the answer

5 0
3 years ago
Read 2 more answers
Find the exact value of the given expression.<br> sin(2cos^-1(5/13))
xeze [42]

Answer:

+120/169 or -120/169

Step-by-step explanation:

  • let cos^{-1}[\frac{5}{13}  ] = \alpha

where, alpha is some angle that satisfies the assumed condition.

  • so, cos\alpha= 5/13

[ taking cos to the other side  or applying cos on both sides]

  • now, substitute this in the given expression
  • sin(2cos^-1(5/13)) = sin(2\alpha )

as sin\beta =  + or -\sqrt{1-(cos\beta) ^{2}

[by general trigonometry formula: cos^{2}[\beta]  +sin^{2}[\beta]=1]

so if  cos\alpha= 5/13, we can get sin\alpha from the above formula as + or - 12/13

(because, after taking square root on both sides we keep + or -]

  • as, sin2\beta  = 2*sin[\beta ]*cos[\beta ]

[by general trigonometry formula]

  • here, now sin[2\alpha ]=2*(+or- 12/13)*5/13\\

so, the final value can be 120/169 or -120/169.

4 0
3 years ago
PLEASE HELP! ITS DUE SOON AND IM STUCK ON THE LASY QUESTION!
Andrej [43]

Answer:

2k + 4 > k + 11

Step-by-step explanation:

Keywords:

more - addition

twice - multiplication

greater than - >

sum - addition

4 more than twice the number k

2k + 4

Greater than

>

Sum of k and 11

k + 11

2k + 4 > k + 11

Solve for k if needed.

2k + 4 > k + 11

2k > k + 7

k > 7

Best of Luck!

6 0
4 years ago
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