Answer:
Mr. Lee takes home 9 kg of chocolate.
Mrs. Scarlet takes home 6kg of chocolate.
Step-by-step explanation:
Mr. Lee has a family of 6 people, and Mrs. Scarlett has a family of 4 people.
Together, the total number of people is 6 + 4 = 10
If we divide evenly the chocolate between all 10, then each one gets the same amount.
Then we need to do the quotient:
15kg/10 = 1.5kg
This means that each person gets 1.5kg of chocolate.
And Mr. Lee has 6 on his family, then the amount of chocolate that Mr. Lee takes home is 6 times 1.5 kg
6*1.5kg = 9kg
Mr. Lee takes home 9 kg of chocolate.
Mrs. Scarlett has a family of 4 people, then she takes home 4 times 1.5kg of chocolate, this is:
4*1.5kg = 6kg
Mrs. Scarlet takes home 6kg of chocolate.
something noteworthy, the y-coordinate for each point is the same, 9⅛, that means is a horizontal line, over which the x-coordinates are at, so since it's a horizontal line, all we need to do is find, what's the distance between 
of course, let's firstly convert the mixed fraction to improper fraction and then check their difference.
![\bf \stackrel{mixed}{5\frac{7}{10}}\implies \cfrac{5\cdot 10+7}{10}\implies \stackrel{improper}{\cfrac{57}{10}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2}{5}-\left[-\cfrac{57}{10} \right]\implies \cfrac{2}{5}+\cfrac{57}{10}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(2)2+(1)57}{10}}\implies \cfrac{4+57}{10}\implies \cfrac{61}{10}\implies 6\frac{1}{10}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%2010%2B7%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B57%7D%7B10%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B2%7D%7B5%7D-%5Cleft%5B-%5Ccfrac%7B57%7D%7B10%7D%20%5Cright%5D%5Cimplies%20%5Ccfrac%7B2%7D%7B5%7D%2B%5Ccfrac%7B57%7D%7B10%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%2010%7D%7D%7B%5Ccfrac%7B%282%292%2B%281%2957%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B4%2B57%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B61%7D%7B10%7D%5Cimplies%206%5Cfrac%7B1%7D%7B10%7D)
Answer:
An acute angle is less than 90°.
An obtuse angle is more than 90°.
Step-by-step explanation:
Sorry if wrong didn't really get the question I'm a little slow
<h2>
Answer:</h2>
The value of x is -1/2
<h2>
Step-by-step explanation:</h2><h3>Question :</h3>
Solve the equation of f(x + 2) = f(x - 2) + 4, where f(x) = 3 + 2x + x^2
<h3>Solution :</h3>
First, we need to split the equation and find the answer to each function
f(x + 2) = 3 + 2(x + 2) + (x + 2)^2
f(x + 2) = 3 + 2x + 4 + x^2 + 4x + 4
<u>f(x + 2) = x^2 + 6x + 11</u>
f(x - 2) = 3 + 2(x - 2) + (x - 2)^2
f(x - 2) = 3 + 2x - 4 + x^2 - 4x + 4
<u>f(x - 2) = x^2 - 2x + 3</u>
Second, we need to find the value of x
f(x + 2) = f(x - 2) + 4
=> x^2 + 6x + 11 = x^2 - 2x + 3 + 4
=> x^2 - x^2 + 6x + 11 = - 2x + 3 + 4
=> 6x + 11 = -2x + 7
=> 6x = -2x - 4
=> 6x + 2x = -4
=> 8x = -4
=> x = -1/2
<h3>Conclusion :</h3>
The value of x is -1/2
The only of these that is a proper set of ordered pairs for this equations is A) (0,-4) (1,2) (3,14)
In order to prove this, you need to put each ordered pair into the equation and prove that it is a true statement. Below are the examples of this for A.
(0, -4)
y = 6x - 4
-4 = 6(0) - 4
-4 = 0 - 4
-4 = -4 (TRUE)
(1, 2)
y = 6x - 4
2 = 6(1) - 4
2 = 6 - 4
2 = 2 (TRUE)
(3, 14)
y = 6x - 4
14 = 6(3) - 4
14 = 18 - 4
14 = 14 (TRUE)
Therefore, each of these ordered pairs works in the equation.
