The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the 
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that 
, 
, 
and 
, then the resulting vector is:
![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (), in degrees, by the following <em>trigonometric</em> expression:
(3)
The bearing of the plane is approximately 178.037°.
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
Answer:
a.51
b.131.5
d.131.5
w.131.5
x.51
y.131,5
z.51
don't know the rest
Step-by-step explanation:
Answer:
A
B
C
Step-by-step explanation:
0.99 is the answer it greater than 0.1
Given that height, h(t) of a tennis ball is modeled by the equation h(t)=<span>-16t^2 + 45t + 7, the time taken for the ball to reach maximum height will found as follows:
at maximum height:
h'(t)=0
but from the equation:
h'(t)=-32t+45=0
solving for t we get
t=45/32
t=1.40625~1.4 seconds
Thus the time taken to reach maximum height is 1.4 seconds
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