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velikii [3]
3 years ago
5

Derek owns a landscape business. He charges a fixed fee of $30 plus $1 per 1,000 square feet of lawn mowed. Derek's earnings (in

dollars) in the past five weeks are {204, 344, 450, 482, 504}. To find the corresponding square footage of lawn mowed, construct a function that models the total area of lawn that Derek mows based on his earnings. Based on Derek's earnings, the corresponding square footage of the lawns he mowed in the past five weeks is

Mathematics
2 answers:
Sliva [168]3 years ago
6 0
Let
x = earnings, dollars
y = area mowed, in 1000's of square feet.

Then the required function is
y = x - 30

Construct a table that shows Derek's weekly earnings versus area mowed.

week       x            y
------- --------  ----------
    1     204         174
    2    344         314
    3    450         420
    4    482         452
    5    504         474
-----   -------   -----------
Total  1984      1834

A graph of y versus x is shown below.

From the table, obtain the total area mowed in the past five weeks as the sum of the y columns, which is 1,834 thousand square feet.

Answer: 1,834 thousand square feet.

antiseptic1488 [7]3 years ago
6 0

Answer:

{174,000, 134,000, 420,000, 452,000, 474,000}

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Ivahew [28]

Answer:

Point (20 , -3) lies on the circle ⇒ (A)

Step-by-step explanation:

The point which lies on the circle must satisfy the equation of the circle

The equation of the circle is x² + (y - 12)² = 25²

<em>Take the left hand side and substitute x and y by the coordinates of each point the answer must equal the right hand side</em>

<em />

A. (20 , -3)

∵ x = 20

∵ y = -3

∴ (20)² + (-3 - 12)² = 400 + (-15)² = 400 + 225 = 625

∵ The right hand side is 25²

∵ 25² = 625

∴ The left hand side = The right hand side

∴ Point (20 , -3) satisfy the equation of the circle

∴ Point (20 , -3) lies on the circle

B. (-7 , 24)

∵ x = -7

∵ y = 24

∴ (-7)² + (24 - 12)² = 49 + (12)² = 49 + 144 = 193

∵ The right hand side is 25² = 625

∴ Point (-7 , 24) does not lie on the circle

C. (0 , 13)

∵ x = 0

∵ y = 13

∴ (0)² + (13 - 12)² = 0 + (1)² = 0 + 1 = 1

∵ The right hand side is 25² = 625

∴ Point (0 , 13) does not lie on the circle

D. (-25 , -13)

∵ x = -25

∵ y = -13

∴ (-25)² + (-13 - 12)² = 625 + (-25)² = 625 + 625 = 1250

∵ The right hand side is 25² = 625

∴ Point (-25 , -13) does not lie on the circle

6 0
3 years ago
What is 2- 1/4 <br> Write your answer as a fraction <br> Meh will mark you
Arlecino [84]

Answer:

1  3/4

Step-by-step explanation:

6 0
3 years ago
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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

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(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

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Hello! Can you please help me on these two problems? =)
poizon [28]

Yeah, I gotta read the questions better.

Perimeter not area.

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P = 12 + 10 + 28 + 24 + 21.26 = 95.26 units

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Step-by-step explanation:

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