A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:
(x,y)→(y,-x).
Then:
- D(−2,4)→D'(4,2)
- E(4,7)→E'(7,-4)
- F(10,3)→F'(3,-10)
- G(8,0)→G'(0,-8)
Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).
Answer:
x=6
B = 20
Step-by-step explanation:
The exterior angle is equal to the sum of the opposite interior angles
55+ 3x+2 = 13x-3
Combine like terms
57+3x = 13x -3
Subtract 3x from each side
57+3x-3x = 13x-3x-3
57 = 10x-3
Add 3 to each side
57+3 = 10x-3+3
60 = 10x
Divide each side by 10
60/10 = 10x/10
6 =x
We also want angle B
B = 3x+2
3*6+2
18+2
20
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