3+(4×12) in word expressions

A test preparation claims that more than 50% of the students who take their test prep course improve their scores by at least 1

satela [25.4K]

Answer:

Step-by-step explanation:

Corresponding scores before and after taking the course form matched pairs.

The data for the test are the differences between the scores before and after taking the course.

μd = scores before taking the course minus scores before taking the course.

a) For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.

Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.

c) The mean difference for the sample scores is greater than or equal to zero

3 0

3 years ago

30% increase on $50 help I need the answer nowww

Bond [772]

Answer:

$65

Step-by-step explanation:

30% of 50 is 15, so 50+15=65.

8 0

3 years ago

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Find two numbers whos diffrence is 16 and the product is 720

antiseptic1488 [7]

Answer:

the numbers who's difference is 16 and the product is 720 is

36 &20

Explanation:

to finding numbers you have to express the equation in a quadratic equation then Factor it.

since the two numbers have a difference of 16 you can say that the first number is x and the second number is x -16 then their product is 720.

x(x-16)=720

x²-16x=720

x²-16x-720=0

(x-36)(x+20)

there are two possible value of x but since you are looking for the positive value of x, choose the positive value of x the first number is 20.

To find the second number

x-16=20

x=20+16

x=36

the second number is 36

Now to check

36-20=16

20*36=720

8 0

3 years ago

With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the

coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is $1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day$

The median is $Median = 38 ^{th} \ girl (subject) = 2 \serving\ of\ fruit\ per\ day$

The third quartile is $3rd Q = 56^{th} \ girl (subject) = 4 \serving\ of\ fruit\ per\ day$

The mean is $\= x = 2.62$

Step-by-step explanation:

From the question we are told that

The total number of girls is n = 74

Generally the median is mathematically represented as

$Median = \frac{\frac{n}{2} +[ \frac{n}{2} + 1] }{2}$

So

$Median = \frac{\frac{74}{2} +[ \frac{74}{2} + 1] }{2}$

=> $Median = \frac{37 +38 }{2}$

=> $Median =37.5 \ girl$

From the histogram $37.5 \approx 38^{th} \ girl$ fall under 2 fruits per day

Generally the first quartile is mathematically represented as

$1st \ Q = \frac{\frac{n}{4} + [\frac{n}{4} + 1] }{2}$

=> $1st \ Q = \frac{\frac{74}{4} + [\frac{74}{4} + 1] }{2}$

=> $1st \ Q = 19 \ girl$

From the histogram $19^{th}$ girl fall under 1 fruit per day

Generally the third quartile is mathematically represented as

$3rd\ Q = \frac{\frac{n}{2} + n }{2}$

=> $3rd\ Q = \frac{\frac{74}{2} + 74 }{2}$

=> $3rd\ Q = 55.5$

From the histogram $55.5 \approx 56^{th} \ girl$ fall under 4 fruits per day

Generally from the histogram table the frequency [number of subjects (girls) ] and the servings of fruit per day can be represented as

Total

x(servings per day ) 0 1 2 3 4 5 6 7 8

f (number of subjects ) 15 11 15 11 8 5 3 3 3 $\sum f = 74$

xf 0 11 30 33 32 25 18 21 24 $\sum xf = 194$

Generally the mean is mathematically represented as

$\= x = \frac{1}{ \sum f} * [\sum xf]$

=> $\= x = \frac{1}{ 74} *194$

=> $\= x = 2.62$

4 0

3 years ago

What are the solutions of the equation 6x2 +5x+1 = 0 ?

STatiana [176]

Answer:

Step-by-step explanation:

6x^2+5x+1=0

Descr= b^2-4ac

Descr= 25-24=1

X1= (-b+√descr)/2a = (-5+1)/12= -1/3

X2= (-b-√descr)/2a = (-5-1)/12= -1/2

6 0

3 years ago

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