Glass melts at a temperature that is higher than 2,600 degrees and less than 2,900 degrees.

In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s

Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 210, \sigma = 38.6$

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 210}{38.6}$

$X - 210 = -1.28*38.6$

$X = 160.59$

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0

3 years ago

I need Help!!!!!!!!!

nalin [4]

Answer:

okay i will answer but i dont see the question

Step-by-step explanation:

8 0

3 years ago

Please help fix my answers this is do tomorrow :( . all the circled ones. Greatly appreciated

Dmitry_Shevchenko [17]

#3 is correct at 120.4

#4 is 15/8...because 3/4+3/4=6/4 (for 20 doors) plus 3/8 (which is half of 3/4 for 5 more doors) equals 15/8 gallons or 1.875 gallons

#5 is $812.50 because if 50 shares cost $125, 325 shares (125×6.5) equals 812.50

7 0

3 years ago

-----.135as a fraction

Mrac [35]

This has to do with place value.
0.135.....the last digit (5) is in the thousandths place....so put it over 1000.
135/1000 reduces to 27/200

6 0

3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :