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Ierofanga [76]
3 years ago
14

Glass melts at a temperature that is higher than 2,600 degrees and less than 2,900 degrees.​

Mathematics
1 answer:
Agata [3.3K]3 years ago
3 0

Answer:

2,700-2,800

Step-by-step explanation:

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Identify the quadratic function from the four functions
Alchen [17]

Quadratic Function is a function that takes the equation form of:

\large \boxed{y = a {x}^{2}  + bx + c}

where a ≠ 0. However the form of Quadratic Function above can also be called "standard form" or general form because it is commonly used when defining the function. Quadratic Functions also have other two forms which are intercept form and vertex form.

<u>Vertex</u><u> </u><u>Form</u>

\large \boxed{y = a {(x - h)}^{2}  + k}

<u>Intercept</u><u> </u><u>Form</u>

\large \boxed{y = (ax - b)(bx - c)}

The intercept form can be expressed as y = (x-a)(x-b) depending on the other perspective.

If you look at all four functions, you will notice that only two of functions have the second degree as highest degree while the third function has third degree as highest and fourth function has fourth degree. Recall the definition of Quadratic Function above that the highest degree of Quadratic Function can only be second degree (squared, x² as example). Therefore we can rule out the x³ and -2x⁴ away.

So our only quadratic functions are:

\large{ \begin{cases}y =  -  {x}^{2}  - 4 \\ y =  {(x - 1)}^{2}  - 7 \end{cases}}

As for the f(x) = -x²-4. The equation is in standard form which is y = ax²+bx+c. The second equation is in vertex form which is y = a(x-h)²+k.

Answer

  • The only quadratic functions are f(x) = -x²-4 and f(x) = (x-1)²-7
  • -x²-4 is in standard form.
  • (x-1)²-7 is in vertex form.

Hope this helps and let me know if you have any doubts.

<em>Als</em><em>o</em><em> </em><em>let</em><em> </em><em>me</em><em> </em><em>know</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>want</em><em> </em><em>me </em><em>t</em><em>o</em><em> </em><em>convert</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>into</em><em> </em><em>other</em><em> </em><em>form</em><em>.</em><em> </em><em>For</em><em> </em><em>ex</em><em>.</em><em> </em><em>convert</em><em> </em><em>the</em><em> </em><em>vertex</em><em> </em><em>form</em><em> </em><em>to</em><em> </em><em>standard</em><em> </em><em>form</em><em>.</em><em> </em>

Happy Learning and Good Luck with your assignment!

4 0
3 years ago
Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.
SCORPION-xisa [38]

Answer:

The solutions are x=-3,\:x=3

Step-by-step explanation:

To factor this cubic polynomial x^3+3x^2-9x-27 you must:

  • Group the polynomial into two sections

x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)

  • Factor out -9 from (-9x-27)

(-9x-27)=-9\left(x+3\right)

  • Factor out x^2 from (x^3+3x^2)

(x^3+3x^2)=x^2\left(x+3\right)

x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)

  • Factor out common term x+3

-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)

x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)

  • Factor x^2-9

x^2-9=\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0

  • Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}

The solutions are

x=-3,\:x=3

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Find the common factor which in this case is 2. Divide numerator and denominator by common factor. You’re left with 19/29. Since 19 and 29 don’t have any common factors it is in its simplest form.
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N aquarium tank holds
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4 years ago
Which expression is equivalent to ?
ivann1987 [24]

Answer:

2x Y,

Step-by-step explanation:

6 0
3 years ago
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