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Alina [70]
3 years ago
6

BRAINIEST TO WHOEVER RIGHT

Mathematics
2 answers:
adoni [48]3 years ago
5 0

Answer:

i know b only Sorry hope this helps tho

Step-by-step explanation:

its 4 because each space is 25% no matter how big or small it is. so if you land on -9 to -5 thats 25% and to -2 thats another 25% total 50% its asking for 75% so you go one more which lands on 4 making it 75%

yKpoI14uk [10]3 years ago
5 0

Answer:

  • THE RANGE OF DATA IS FROM -9TO 6 i.e 15
  • 75% of data lies between -9 and 4 as there are 16 units between -9 and 6 and 75%of 16 is 12 and -9+ 12 = 3 which is the right answer
  • The interquartile range of data is -2+-1 /2=-1.5

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Please help, algebra two problem
cricket20 [7]

Answer: -12

Step-by-step explanation:

6 0
3 years ago
Find SY and XY. PLEASE HELP ME IT IS DUE SOON IF YOU DONT KNOW DO NOT ANSWER
alina1380 [7]

Answer:

SY = 16

XY = 12

Step-by-step explanation:

15/20 = 12/SY

15SY = 240

SY = 16

15/20 = 9/XY

15XY = 180

XY = 12

5 0
3 years ago
Select the THREE equations that this diagram could represent.
Vladimir [108]

<u>Question </u>

Select the three equations that this diagram could represent.

<u>                                                                                                                                     </u>

<u>Answer</u>

<em>Well, we first have to find out what the diagram says.</em>

<em>So what the diagram says is that  18 + 18 + 18 = 54.</em>

<em>Given this information,  we have to figure what other answers = 54.</em>

<em>Therefore the answers are </em>

(A) 18 * 3 = 54.

(D) 54/18 = 3

(E) 54/3 =18

6 0
3 years ago
Which arc is a minor arc? <br><br> SQ<br><br> PSR<br><br> PS
laila [671]

Answer:

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4 0
2 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0
3 years ago
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