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Marrrta [24]
4 years ago
12

A big cruise ship dropped anchor off the Caribbean island of Barbuda. The heavy anchor was released from a height of 545454 mete

rs above the water's surface, and it fell at a constant rate. After 353535 seconds, the anchor was 999 meters below the water's surface.
How fast did the anchor drop?
Mathematics
2 answers:
Iteru [2.4K]4 years ago
5 0
It went from 54 meters above the surface to 9 meters below the surface...
54 to the surface (0) = 54....from 0 to -9 = 9....so it fell (54 + 9) = 63 meters.

so if it fell 63 meters in 35 seconds, then it fell (63/35) = 1.8 meters per second <===
UNO [17]4 years ago
4 0

Answer:

1.8 meters in 30 seconds

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(Refer figure)

Given quadrilateral ABCD is a parallelogram.

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Since by properties of parallelogram, the both pairs of opposite sides of a parallelogram are parallel.

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Using (1) for given parallelogram ABCD; we get,

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Therefore x = 114° and y = 66°.

Using (2) to check whether the two consecutive angles are supplementary.

( m∠A + m∠D ) =  ( m∠B + m∠C ) = ( m∠C + m∠D ) = 66° + 114° = 180°

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