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prohojiy [21]
4 years ago
14

The function h(x)=x2+3 and g(x)=x2-6. If g(x)=h(x)+k, what is the value of k?

Mathematics
1 answer:
KiRa [710]4 years ago
7 0

Answer:

-9 =k

Step-by-step explanation:

h(x)=x^2+3 and g(x)=x^2-6

g(x)=h(x)+k

Substitute in

x^2-6 = x^2+3 +k

Subtract x^2 from each side

x^2 -x^2-6 = x^2-x^2+3 +k

-6 = 3+k

Subtract 3 from each side

-6-3 = 3-3+k

-9 =k

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6 0
3 years ago
Hey I have a link to the question since its kinda complicated
Natalija [7]
Anyway

so the recursive rule tells the relationship between the previous term and the term we want to find

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8 0
4 years ago
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3(x + 10) + 6 = 3(x + 12)<br><br> O zero<br> o one<br> O two<br> o infinitely many
Masteriza [31]

Answer: Infinitely Many Solutions

Step-by-step explanation:

3(x+10)+6=3(x+12)

3x+30+6=3x+36

3x+36=3x+36

Infinitely Many Solutions

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5 0
3 years ago
If f(x)=5^x+2x and g(x)=3x-6 <br><br> find (f+g)(x)
azamat

Answer:

(f+g)(x) =  5^x+5x-6

Step-by-step explanation:

f(x)=5^x+2x

g(x)=3x-6

(f+g)(x) =  5^x+2x+3x-6

Combine like terms

(f+g)(x) =  5^x+5x-6

3 0
3 years ago
The sum of two consecutive even integers is 186. What are the two numbers?
ozzi

Answer: 92 and 94

Step-by-step explanation:

x = first number

x + 2 = second number

x + x + 2 = 186

simplify

2x + 2 = 186

subtract 2 from both sides

2x = 184

divide both sides by 2

x = 92

92 + 2 = 94

The numbers are 92 and 94.

6 0
3 years ago
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