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Tomtit [17]
3 years ago
15

A zebra ran at a speed of 20 feet per second.what operation should you use to find the distance the zebra ran i 10 seconds?

Mathematics
2 answers:
Anna [14]3 years ago
6 0

Answer:

Distance, d = 1=200 feets

Step-by-step explanation:

Given that,

Speed of zebra, v = 20 ft/s

Time, t = 10 s

Let d is the distance covered by the zebra. The product of speed and time taken by zebra is called total distance covered. Here, the multiplication operation is used as :

d=v\times t

d=20\ ft/s\times 10\ s

d = 200 feets

So, the distance covered by the zebra is 200 feets. Hence, this is the required solution.

Nookie1986 [14]3 years ago
4 0
The operation you should use is division
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Answer:

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Step-by-step explanation:

Given

Surface area of sphere, T =452.16

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how many times larger is the radius of sphere X than the radius of sphere T?

Finding radius of both spheres:

Surface area of sphere is given as

A=4πr^2

Now putting value of Ta=452.16 in above formula

452.16=4πrt^2

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Taking square root on both sides

rt=5.99

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rx^2=1808.64/4π

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rx=11.99

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rx/rt=11.99/5.99

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each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
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if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

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Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

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But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

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To learn more about Probability visit: brainly.com/question/29508225

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Answer:

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