Answer:
Step-by-step explanation:
hello :
let f this function
the roots of this function are : -1 , 0 ,6 so ; f(x) = ax(x+1)(x-6)
now calculate : a ....but this graph passes by : (1, -10) means f(1) = -10
put : x=1 and f(x) = -10
-10 = a(1)(1+1)(1-6)
-10a = -10 so : a= 1
conclusion :
48f^2-110f+63
We multiple every part of first sum with every prt of the 2nd sum:
(6f-7)(8f-9)=48f^2-54f-56f+63=
b. expository
4,-7 = 11
and
6, -9 = 15
