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3 years ago

6

soccer practice began at 2:30 p.m. and then stopped at 3:00 p.m. because of rain. during this time, through what fraction of a c

ircle did the minute hand turn? how many degrees did the minute hand turn.

1 answer:

n200080 [17]3 years ago

7 0

The match took 30 minutes.

A minute watch covers 360 degrees every 60 minutes. In 30 minutes the watch therefore covers 180 degrees.

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What is the conjugate<br> 2/4+3i

kondor19780726 [428]

*) 2/4+3i
2+3i
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3 years ago

I need help on problem number 12 and 14 plzzzz

Eva8 [605]

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3 years ago

Evaluate each expression when x = 8, and z = 10

sveticcg [70]

Answer:

x = 2

y = 4

z = 8

1. xy

10

2. x + z

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3. z - y

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4. x + y + z

14Step-by-step explanation:

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2 years ago

Ganezh [65]

Answer:

168 meters squared

Step-by-step explanation:

So we know that Jake walked from b to c and d meaning he didn't go from a to b, but we also know that scarlet walked a to b so to find the length we can subtract scarlet's walk by jake's walk or 38-31 which is 7.

So we know the length of one side is 7 so this means we have side a to b and c to d, but we still need to know b to c. So what we can do is get the length of a b c and d and isolate it so that we only have b to c. To do this we get the length of 7 and double it which is 14 and take it away from the 38m

38-14=24

so now we know that the side is 24 and we can solve for the area

24*7=168

so the answer is 168 meters squared

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3 years ago

A basketball player stands near the middle of the court and throws the ball toward the basket.

kompoz [17]

Answer:

A function to represent the height of the ball in terms of its distance from the player's hands is $y=\frac{-1}{54}(x-18)^2+12$

Step-by-step explanation:

General equation of parabola in vertex form $y= a(x-h)^2+k$

y represents the height

x represents horizontal distance

(h,k) is the coordinates of vertex of parabola

We are given that The ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.

So,(h,k)=(18,12)

Substitute the value in equation

$y=a(x-18)^2+12$ ---1

The ball leaves the player's hands at a height of 6 feet above the ground and the distance at this time is 0

So, y = 6

So, $6=a(0-18)^2+12$

6=324a+12

-6=324a

$\frac{-6}{324}=a$

$\frac{-1}{54}=a$

Substitute the value in 1

So, $y=\frac{-1}{54}(x-18)^2+12$

Hence a function to represent the height of the ball in terms of its distance from the player's hands is $y=\frac{-1}{54}(x-18)^2+12$

8 0

3 years ago