If the point is on the unit circle:
x² + (√3/3 )² = 1²
x² + 3/9 = 1
x² + 1/3 = 1
x² = 1 - 1/3
x² = 2/3 / √
x = √2/√3 · √3/√3 = √6 / 3
Answer: A ) square root (6) / 3
Answer:
The solution to the set of inequalities is on the shaded regions.For example point (10,10)
Step-by-step explanation:
The equations are
plot the equations on a graph tool as shown below and visualize the solution on the shaded areas.
The goal is to find the area of a pentagon with side length 8.
We can find the area of a pentagon very easily by splitting it up into 10 congruent right triangles with the apothem as the height. The base of one of these triangles would be 4. The base angle would be 54 degrees, because it's half of the angle of a regular pentagon.
Using trig we find that the height of this triangle/apothem of the pentagon is equal to 4tan(54 degrees), which is about 5.506.
The area of a triangle is bh/2, so...4*5.506/2 = 11.011 in².
Times 10 triangles is 110.11 in².
The orthocenter of an obtuse triangle always lies : C. On the outside of the triangle
<span>Attitude of an obtuse triangle will not go through the midpoint line of the triangle and the three points of the triangle will intersect with each other at some point, so it must lies outside of the triangle</span>
Answer:
9(y-5)/10(y-1)
Step-by-step explanation:
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