Its OP I am working on this right now and got a hundred on a topic test i would know
You can use the pythagorean theorem. Make sure that you put the measurements in the right places though. Since 11 is the measure of the hypotenuse, 11 has to be c. When you plug in the information that you have, it should look like this:
8^2 + b^2 = 11^2
Square 8 and 11.
64 + b^2 = 121
Subtract 64 from 121
121 - 64 = 57
The new equation is:
b^2 = 57
Now take the square root of both sides to get b by itself.
b = about 7.5
Answer: The height of the triangle is 7.5
***** Note: I rounded the answer ********************************************
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
The answer to the problem would be Y=31.