All categories

3 years ago

What number is equal to 144 when its squared

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

When 144 is squared, it is equal to 12.

Vadim26 [7]3 years ago

6 0

The answer would be 12

You might be interested in

Please help, I am terrible at math

Zarrin [17]

Answer:

the correct option is D (12 units, 14 units, 10 units)

Step-by-step explanation:

P= 36

2t + 2 + 2t + 4 +2t = 36

combine like terms

6t + 6 = 36

subtract 6 from both sides

6t = 30

30/6 = 5

T = 5 so plug the t in the other equations

2(5) + 2 = 10 + 2 = 12

2(5) + 4 = 10 + 4 = 14

2(5) = 10

To check combine all the numbers above and you would get 36

3 0

3 years ago

if a rectangle is twice as long as it wide and has a perimeter of 48 inches, what is the area of the rectangle

luda_lava [24]

Answer: 128 $in^{2}$

Step-by-step explanation:

Let the width be W then the length will be 2W since it is twice as long as it width.

The formula for calculating the perimeter of a rectangle is given by :

P = 2 ( L + W )

48 = 2 ( W + 2W )

48 = 2(3W)

48 = 6W

Divide through by 6

Therefore:

W = 48/6

W = 8 inches

This means that the Length is 2 x 8 = 16 inches

Area = Length x breadth

Area = 16 x 8

Area = 128 $in^{2}$

4 0

3 years ago

Your digital camera has a 512 megabyte memory card. You take low resolution pictures requiring 4 megabytes of memory each and hi

lys-0071 [83]

128 with 4 megabytes and 64 with 8 megabytes

3 0

3 years ago

If a, b, and c are solutions to the

Alik [6]

Answer:

$\displaystyle 10c - 6a = 110$

Step-by-step explanation:

We are given the equation:

$\displaystyle 3x^3 - 25x^2 -50x = 0$

Where a, b, and c are solutions to the equation and where a < b < c, we want to determine the value of 10c - 6a.

To find the solutions of the equation, we can factor:

$\displaystyle \begin{aligned} 3x^3 - 25x^2 -50x & = 0 \\ \\ x(3x^2 - 25x -50) & = 0 \\ \\ x(3x+5)(x-10) & = 0 \end{aligned}$

From the Zero Product Property:

$\displaystyle x = 0 \text{ or } 3x + 5 = 0 \text{ or } x - 10 = 0$

Solve for each case:

$\displaystyle x = 0 \text{ or } x = -\frac{5}{3} \text{ or } x = 10$

We can see that -5/3 < 0 < 10. Thus, a = -5/3, b = 0, and c = 10.

Therefore:

$\displaystyle \begin{aligned} 10c - 6a & = 10(10) - 6\left(-\frac{5}{3}\right) \\ \\ &= 100 + 10 \\ \\ & = 110 \end{aligned}$

3 0

3 years ago

Find all solutions to the given equations (x-3)(x+2)=0

Stells [14]

(x-3)(x+2)=0

x-3=0 x+2=0

x=3 x=-2

Answer: x=3 , -2

8 0

3 years ago