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elixir [45]
4 years ago
14

0.719 rounded to the nearest hundredth

Mathematics
2 answers:
docker41 [41]4 years ago
8 0

Answer:

0.719 rounded to the nearest hundredth is 0.720

Step-by-step explanation:

9 is more than 5, so you round up, and the next hundredth is 2, so you get 0.720.

<em>Hope this helps!!!  Brainliest would be appreciated</em>

lapo4ka [179]4 years ago
4 0

Answer:

0.72

Step-by-step explanation:

hope i helped

pls mark brainliest im trying to level up

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The function(t)--4.87+18.75 is used to model the height of an object projected in the air, where h() is the height in
NNADVOKAT [17]

The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.

<h3>How to calculate the domain of the function?</h3>

In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:

0= -4.87t² + 18.75t.

4.87t(-t + 3.85) = 0

t = 0 or t = 3.85.

Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).

<h3>How to calculate the range of the function?</h3>

h(t) = -4.87t² + 18.75t

h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)

h(t) = -4.87(t - 1.925)² + 18.05

Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).

Read more on domain here: brainly.com/question/17003159

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2 years ago
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Please help please thanks
Alina [70]

Answer:

A

Step-by-step explanation:

Newton's third law states that for every force, there is an equal and opposite reaction. For example, if you collide two objects together, all of the forces in the system would cancel out because energy conserved with the opposite and equal reactions.

Between two examples (2 identical billiard balls and 2 different toy cars), the easiest way to demonstrate Newton's third law is using the 2 balls, since they are identical in shape and mass. When pushing the two balls in the exact same way with the SAME force, the net force of the equation is basically 0;

F_f = F_1 + F_2 = ma - ma = 0

Therefore, A is correct.

If you pushed a toy car and a toy truck towards each other using the same force, the outcome would not be completely opposite since F = ma and masses are different. Instead, to have a completely opposite and equal reaction, the resulting direction and forces are different. The lighter car would accelerate more in the opposite direction to compensate for the lighter mass. Therefore, B is wrong because even though they are different sizes, newton's third law still happens in the resulting direction and forces, but are simply harder to explain due to so many differing factors.

C is wrong, because diameter of two objects has no correlation to the net force equations. Even if two objects have the same diameter, they could have different masses, shapes, elasticity, etc.

D is wrong, because it goes against Newton's 3rd law. Newton's 3rd law is a LAW. Meaning, it is ALWAYS true (unless in some distant future it's disproven). In any and every collision, energy is conserved in some way that net forces equal 0; either in friction, gravitational force, or resulting force, the net force is always 0.

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3 years ago
The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators
frosja888 [35]

Answer:

(x+2)(x-2) -1(3x)=(x-3)(x-2)

Step-by-step explanation:

x+2/3x - 1/x-2 = x-3/3x

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LCD is (3x)(x-2). so we multiply the whole equation by LCD

(3x)(x-2)(\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x})

We multiply each term by LCD

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(x+2)(x-2) -1(3x)=(x-3)(x-2)

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$127.68 interest. $2027.68 total amount.
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In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) =x2 to the number of x-intercepts in
Natalija [7]
Important:  Please use " ^ " to indicate exponentiation:

<span>"f(x) =x^2 to the number of x-intercepts in the graph of g(x) = x^2 +2."

Notes:  the graph of f(x) = x^2 is a vertical parabola that opens up.  It has its vertex at (0,0).  This is the only point at which f(x)=x^2 has a horiz. intercept.

g(x) = x^2 + 2 has a graph that looks the same as that of f(x) = x^2, EXCEPT that the whole graph is moved 2 units UP.  This new graph never touches or intersects the x-axis.  Therefore, g(x) has NO horiz. intercepts (no x-int.).

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