Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
If Jenni get one page closer to Wren every night and Wren has read 8 more pages then is will take Jenni 8 more nights to catch up to Wren. They will be on page 30 in their book.
For solving this question we will use the relationship between the range of data and the spread of data. The relationship is that "Higher the Range of the Data, Higher is the Spread and lower the range of the data then lower is the spread".
So, keeping in mind this definition let us proceed and check each option and measure their range.
We know that Range is measured as
Range=(Highest Value of the Data)-(Lowest Value of the Data)
a. 13.7-3.1=10.6
b. 423.6-1.3=422.3
c. 38.4-7.2=31.2
d. 231.4-5.5=225.9
As we can see Option b. has the largest range and as range is a measure of spread then option b is the distribution which has the largest spread.
Without the discount each book is 16.25 with the discount theyre 15 each
Answer:
e^-1.6094 = 0.2
Step-by-step explanation:
The inverse of In is e
If In 0.2 = -1.6094
Then e^-1.6094 = 0.2
