When looking at the graph of a 5th degree function, how can you determine if all of the zeros of the function are real?

Mathematics

1 answer:

Finger [1]3 years ago

4 0

Answer:

If it cuts x-axis 5 times.

Step-by-step explanation:

When we look at the graph of a function we can see its real roots by looking at its graph

The intersecting points that is the number of times a line cutting x-axis will be the real root of the function

So, by looking at the 5th degree function the number of time that function cuts x-axis will be the number of real roots.

So, if we need to say all the zeroes or roots of the function are real means it will cut the x-axis 5 times.

Because a function will have the root equal to its degree.

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If f(x)=3 x -1 and g(x)=0.03x^3-x+1 an approximate solution for the equation f(x)=g(x) is

lubasha [3.4K]

Answer:

x ≈ {-11.789, +0.501, 11.288}

Step-by-step explanation:

The cubic g(x) - f(x) = 0 has three real solutions. It can be rewritten as ...

$g(x)-f(x)=0\\\\0.03x^3-x+1-(3x-1)=0\\\\0.03x^3-4x+2=0$

Since the solutions are irrational, they are best found using a spreadsheet or graphing calculator. My favorite graphing calculator shows the approximate solutions below.

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<em>Comment on the problem statement</em>

Your expression for f(x) is ambiguous in that many Brainly questions have the exponentiation indicator replaced by a blank: 3 x -1 often means 3^x -1 and sometimes means 3^(x-1). We have taken the expression at face value and have assumed it is a linear expression. If otherwise, the problem is basically worked the same way: write a function h(x) = g(x) - f(x) and look for solutions to h(x) = 0. Graphing can be useful.