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Yuri [45]
3 years ago
12

11. What method can be used to prove these two triangles are congruent?

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0
This would be SAS. If that’s wrong I’m sorry but it’s the only thing that makes sense, the dashes indicate they are the same and then the circle at the point also indicates that they’re the same so you have two sides and one angle that are the same, so it should be SAS.
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After reading 80% of her e-mails in her inbox, Danette still has M unread emails. Which of the following expressions could repre
Fofino [41]

Answer:

m/(1 - .8)

Step-by-step explanation:

She read 80% of her emails, which is .8 of the total.  So her unread emails would be 100% - 80% = 1 - .8

that means me can be written as:

m = (1 - .8)t

where t is the total

If we solve for t, we get:

t = m/(1 - .8)

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!
musickatia [10]
Let us model this problem with a polynomial function.

Let x =  day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.

Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅

Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
|   1     1    1    1    1  |  | a₁ |      | 42 |
| 2⁴  2³  2²  2¹  2⁰  |  | a₂ |      | 26 |
| 3⁴  3³  3²  3¹  3⁰   |  | a₃ |  =  | 61 |
| 4⁴  4³  4²  4¹  4⁰   |  | a₄ |      | 65 |
| 5⁴  5³  5²  5¹  5⁰  |  | a₅ |      | 56 |

When this matrix equation is solved in the calculator, we obtain
a₁ =      4.1667
a₂ =  -55.3333
a₃ =  253.3333
a₄ =  -451.1667
a₅ =   291.0000

Test the solution.
y(1) = 42  
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56

The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.

Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631


3 0
3 years ago
Read 2 more answers
I need help on it, I don’t know what I’m supposed to do
bogdanovich [222]

Answer:

The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.

Step-by-step explanation:

See the attached diagram.

The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.

Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45

Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x

So, (42x + 43x + 44x + 45x) = 400

⇒ 175x = 400

⇒ x = 2.2988.

So, PQ = 42x = 96.55 ft.

QR = 43x = 98.85 ft.

RS = 44x = 101.15 ft and  

ST = 45x = 103.45 ft

(Answer)

6 0
3 years ago
8) A pyramid has a rectangluar base with length 12 km and width of 5 km. If the volume is 200
SashulF [63]

Hi there!

\large\boxed{h = 10km}

We know that the equation for the volume of a pyramid is:

V = 1/3(bh)

We know that:

V = 200 km³

b = 12 × 5 = 60 km²

We can plug these into the equation:

200 = 1/3(60)(h)

Simplify:

200 = 20h

Divide both sides by 20:

200/20 = 20h/20

h = 10 km

6 0
3 years ago
Write x2 - 12x + 8 = 0 in vertex form.
antiseptic1488 [7]
(x-4)^2-19=y
you first add the three to the other side, then add 16 on both sides, make the left side x-4 squared, and lastly you subtract 19 from both sides.
3 0
3 years ago
Read 2 more answers
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