Answer:
f = 2
g = 8
h = -9
k = 40
m = 1
Step-by-step explanation:
Equation 1:
23f - 17 = 29
Add 17 to both sides. This undoes the -17.
23f = 29 + 17
Add 17 to 29 to get 46.
23f = 46
Divide both sides by 23. This undoes the multiplication by 23.
f = 46/23
Divide 46 by 23 to get 2.
f = 2
Equation 2:
2(3g + 4) = 56
Divide both sides by 2. This undoes the multiplication by 2.
3g + 4 = 56/2
Divide 56 by 2 to get 28.
3g + 4 = 28
Subtract 4 from both sides. This undoes the +4.
3g = 28 - 4
Subtract 4 from 28 to get 24.
3g = 24
Divide both sides by 3. This undoes the multiplication by 3.
g = 24/3
Divide 24 by 3 to get 8.
g = 8
Equation 3:
h + 9 = 0
Subtract 9 from both sides. This undoes the +9.
h = 0 - 9
Any number subtracted from 0 gives its negation.
h = -9
Equation 4
3(k - 8) = 96
Divide both sides by 3. This undoes the multiplication by 3.
k - 8 = 96/3
Divide 96 by 3 to get 32.
k - 8 = 32
Add 8 to both sides. This undoes the -8.
k = 32 + 8
Add 8 to 32 to get 40.
k = 40
Equation 5:
5m - 5 = 0
Add 5 to both sides. This undoes the -5
5m = 0 + 5
Anything plus 0 gives itself.
5m = 5
Divide both sides by 5. This undoes the multiplication by 5
m = 5/5
Anything divided by itself gives you 1.
m = 1
Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
Answer:
daw
Step-by-step explanation:
Answer:
The component form of the vector P'P is 
Step-by-step explanation:
The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;
The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7
The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2
The component form of the vector P'P =
