We need to find the composition function between these functions to verify if these functions are inverses. If f[g(x)] and g[f(x)] are equal to x they are inverses.

1)

Let's find f[g(x)] and simplify.

$f[g(x)]=\frac{1}{2}g(x)+\frac{3}{2}$

$f[g(x)]=\frac{1}{2}(4-\frac{3}{2}x)+\frac{3}{2}$

$f[g(x)]=\frac{7}{2}-\frac{3}{4}x$

As f[g(x)] is not equal to x, these functions are not inverses.

Let's find f[g(x)] and simplify.

$f[g(n)]=\frac{-16+(4n+16)}{4}$

$f[g(n)]=\frac{-16+4n+16}{4}$

$f[g(n)]=\frac{4n}{4}$

$f[g(n)]=n$

Now, we need to find the other composition function g[f(x)]

Let's find g[f(x)] and simplify.

$g[f(x)]=4(\frac{-16+n}{4})+16$

$g[f(x)]=-16+n+16$

$g[f(x)]=n$

Therefore, as f[g(n)] = g[f(n)] = n, both functions are inverses.

I hope it helps you!

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Step-by-step explanation:

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Can anyone help me with this​

Can anyone help me with this