Hey, so x would be -10. If I need to type the work out I can just let me know.
Answer:
Step-by-step explanation:
There is a relationship between lines that are perpendicular. Their slopes are negative reciprocals of each other. Example: if one line has a slope of 4/3 then a line with the slope of -3/4 is perpendicular to it (they intersect at right angles).
So to find the slope of a line perpendicular to y = -2/3x + 4 we must know the slope of it. The slope, when the line is in the slope-intercept form (aka y = mx + b), is the multiplier in front of the "x" so in this case it is -2/3. So a line perpendicular to it has a slope of 3/2.
Now that we know the slope (m = 3/2) we can find the equation of the line that has a slope of 3/2 but goes through the point (-2, -2) in a couple of ways.
1) Use the slope-intercept form of a line and plug in the values of x = -2 and y = -2 (from the point (-2, -2) like this:
y = mx + b
y = 3/2x + b
-2 = 3/2(-2) + b
-2 = -3 + b
1 = b
So y = 3/2x + 1
2) We can use the point-slope equation y - y1 = m(x - x1) which works great if you know the value of m (we do, m = 3/2) and some point (x1, y1) on the line (and we do, (-2, -2); so x1 = -2 and y1 = -2):
y - y1 = m(x - x1)
y - y1 = 3/2(x - x1)
y - (-2) = 3/2(x - (-2))
y + 2 = 3/2(x + 2)
Although it looks different than the other equation, it is really the same. Just distribute and combine like-terms and you'll see it's the same. So either is an acceptable answer for this quest
Answer:
x = -19
y = 55
Step-by-step explanation:
Given:
y = –3x – 2 (rearrange)
3x + y = -2 -----> eq1
5x + 2y = 15 -----> eq2
multiply eq1 by 2:
6x + 2y = -4 -------> eq 3
By elimination: subtract eq2 from eq 3
( 6x + 2y) - (5x+2y) = -4 - 15
x = -19 (Answer)
substitute x = -19 into eq1
3(-19) + y = -2
-57 + y = -2
y = -2 + 57 = 55 (Answer)
W- (3,4)
Z- (-1,1)
X-(-1,-3)
Y-(-4,1)
I would say 22 because 30% of 72 is 21.6 so i rounded up hope i helped