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3 years ago

What is the equation of the line that has a slope of 4 and passes through then point (3,-10)?

Mathematics

1 answer:

Fynjy0 [20]3 years ago

7 0

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Substitute the x and y values into the equation:

y = mx + c

'm' is the slope, which we know is 4

-10 = 4(3) + c

- 10 = 12 + c

c = -22

The equation is y = 4x -22

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

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Complete the factored form.<br> 45x2 + 6x - 7 = (3x - 1)( )

leonid [27]

Answer:

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Step-by-step explanation:

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3 years ago

4. If the sides of a square measure 9V3 units, then find the length of the diagonal.

Nitella [24]

Answer:

Step-by-step explanation:

To find the diagonal, use Pythagorean theorem,

diagonal² = side² + side²

= (9√3)² + (9√3)²

= 9²(√3)² + 9²(√3)²

= 81*3 + 81*3

= 243 + 243

= 486

diagonal = √486 = 22.05 units

7 0

3 years ago

Complementary of supplementary? Find the value of x

prohojiy [21]

Answer: x=6

The two angles shown in each are complementary because they add up to 90°.

10 & 12 would be supplementary to one another because they would add up to 180°.

Step-by-step explanation:

We know that on both 10 & 12 the angles add up to equal 90° so...

10. 8x+7x=90

15x=90

x=6

12. it's the same in pic as 10

The two angles shown in each are complementary because they add up to 90°.

10 & 12 would be supplementary to one another because they would add up to 180°.

5 0

3 years ago

Seventy-eigth hundred-thousandths

s2008m [1.1K]

The decimal number for seventy eight hundred-thousandths is 5.

<h3>What is decimal number?</h3>

A decimal is a number that consists of a whole and a fractional part

The decimal numeral system is the standard system for denoting integer and non-integer numbers.

What is the decimal number for seventy eight hundred-thousandths?

= 78 x 10⁻⁵

<u>note</u>: a hundred thousandth = 10⁻⁵

= 0.00078

Thus, the decimal number for seventy eight hundred-thousandths is 5.

Learn more about decimal number here: brainly.com/question/1827193

#SPJ1

8 0

1 year ago

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.85

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 20

$\mu$ = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u> $\mu$ <u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.85-1.96 \times {\frac{0.75}{\sqrt{20} } }$ , $4.85+1.96 \times {\frac{0.75}{\sqrt{20} } }$ ]

= [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.56

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 16

$\mu$ = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u> $\mu$ <u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98 {As the critical value of z at 1% level

of significance are -2.3263 & 2.3263}

P(-2.3263 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.3263$ ) = 0.98

P( $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.98

<u>98% confidence interval for</u> $\mu$ = [ $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } }$ , $4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } }$ ]

= [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0

4 years ago