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3 years ago

Tammy drove 522 miles in 9 hours.

Mathematics

2 answers:

Rudik [331]3 years ago

6 0

Answer:

V=d/t=522/9=58

t=d/V=638/58=11h

Crazy boy [7]3 years ago

4 0

He is driving at 58 mph, so he’d reach the destination in 11 hours

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Kendrick and Rishaun spend a total of $112 at an amusement park. They spend $32 on parking, $12 on lunch, and the rest on 2 admi

Elena-2011 [213]

Each ticket is $34 each
32+12+2x=112
44+2x=112
-44 -44
———————-
2x=68
— —
2 2
x=$34

6 0

3 years ago

The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in

garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

7 0

3 years ago

Find the diameter of the circle with the given radius.<br> 5. 20 feet

guajiro [1.7K]

Answer:

40 feet

Step-by-step explanation:

the diameter is just Rx2 (R being the radius)

7 0

2 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

3 years ago

Ogether, teammates pedro and ricky got 2675 base hits last season. pedro had 283 more hits than ricky. how many hits did each pl

kondor19780726 [428]

Let Ricky = x; so equation: x + (x+283) = 2675 ; Re-arrange so x = Ricky = 1196 hits with Pedro 1196 + 283 = 1479.

7 0

3 years ago