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3 years ago

7

Tammy drove 522 miles in 9 hours.

2 answers:

Rudik [331]3 years ago

6 0

Answer:

V=d/t=522/9=58

t=d/V=638/58=11h

Crazy boy [7]3 years ago

4 0

He is driving at 58 mph, so he’d reach the destination in 11 hours

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In 2 minutes, Nolan unloads 10 boxes from the truck. Write the equation for the relationship between x and y.

Anna11 [10]

Answer:

2x = y

Step-by-step explanation:

x = minutes

y = 10 boxes

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3 years ago

What is the volume of square pyramid with base edges of 32 cm and a slant height of 34 cm?

julsineya [31]

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4 years ago

Read 2 more answers

Use the rectangle hexagon with side length 10 meters to fill in the missing information

Vlada [557]

Answer:

$A_h=150\sqrt{3}\ m^2$

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

$x=5 m$

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

$\theta=360/12=30^o$

Now we have $\theta$ , the height of the triangle y is easily found by

$\displaystyle tan30^o=\frac{x}{y}$

Solving for y

$\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}$

The value of z can be found by using

$\displaystyle sin30^o=\frac{x}{z}$

$\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10$

The area of the triangle is

$\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}$

The area of the hexagon is 12 times the area of the triangle, thus

$\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}$

$\boxed{A_h=150\sqrt{3}\ m^2}$

6 0

3 years ago

Someone please help me find the surface area of the cone in the picture below

Dafna1 [17]

this is the formula:
A=<span><span>πr</span><span>(<span>r+<span><span>h2</span>+<span>r2</span></span></span><span>)
Answer: 151.58 in</span></span></span>

5 0

3 years ago

Ms. berkin is dividing her 4 1/2-foot by 6-foot bulletin board into 4 sections with ribbon stretched from each corner to the opp

Mnenie [13.5K]

Answer:

15 feet.

Step-by-step explanation:

A bulletin board has been shown in the figure below.

Where the width of the board AB = DC = $4\frac{1}{2}$ = 4.5 feet

and the length of the board AD = BC = 6 feet

As Ms. Berkin is dividing the board by stretching the ribbons to the opposite corners so the length of ribbons will be AC and BD.

In right angle triangle <em>ADC</em>, using Pythagorean Theorem,

$AC^2=AD^2+DC^2$ = $6^2+4.5^2=36+20.25=56.25$

$AC= \sqrt{56.25} = 7.5$ feet

Similarly in triangle <em>BDC</em>,

$BD^2=BC^2+DC^2 = 6^2+4.5^2=36+20.25 =56.25$

$BD=\sqrt{56.25} = 7.5$ feet

Thus, total length of the ribbon used = AC + BD = 7.5 + 7.5 = 15 feet

3 0

4 years ago