The tangent makes an angle of 90 degrees with the circle.
x + 29 + 90 = 180
x = 180 - 29 - 90
x = 61
x = 61°
Answer:
K(x) =
( curvature function)
Step-by-step explanation:
considering the Given function
F(x) = 
first Determine the value of F'(x)
F'(x) = 
F'(x) = -10x
next we Determine the value of F"(x)
F"(x) = 
F" (x) = -10
To find the curvature function we have to insert the values above into the given formula
K(x) ![= \frac{|f"(x)|}{[1 +( f'(x)^2)]^{\frac{3}{2} } }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%7Cf%22%28x%29%7C%7D%7B%5B1%20%2B%28%20f%27%28x%29%5E2%29%5D%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%7D)
K(x) =
( curvature function)
Answer:
The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Step-by-step explanation:
We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.
Let X = <u><em>lengths of pregnancies in a small rural village</em></u>
SO, X ~ Normal(
)
Here,
= population mean = 262 days
= standard deviation = 17 days
<u>Now, the 68-95-99.7 rule states that;</u>
- 68% of the data values lies within one standard deviation points.
- 95% of the data values lies within two standard deviation points.
- 99.7% of the data values lies within three standard deviation points.
So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;
[
,
] = [262 - 17 , 262 + 17]
= [245 days , 279 days]
Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Answer:
14.3%
Step-by-step explanation:
There is only one four out of 7 total numbers.
1/7 = 0.142857 = 14.29%