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konstantin123 [22]
3 years ago
7

Which statement is true about f(x)+2=1/6 |x-3|

Mathematics
2 answers:
FromTheMoon [43]3 years ago
7 0

Answer:

Answer choice  D is correct.

Step-by-step explanation:

The graph of f(x) has a range of f(x) > -2

ohaa [14]3 years ago
4 0

Answer:

The range of f(x) is f(x) > -2 and option D is correct.

Step-by-step explanation:

HOPE THIS IS THE ANSWER YOU WERE LOOKING FOR

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Can anyone please tell me how to do this​
andrew11 [14]

Hello there, this problem is just basic addition, here is what it would look like

52.31+25.90

Solve it and we get 78.21

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2 years ago
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Find the Slope of lines passing through the points: (4,5) and (6,7)​
kupik [55]

the answer is 0.6 you gotta divide and multiply

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2 years ago
This is on a online thing soif you know the answer can you tell me ASAP<br><br><br> thanks
grigory [225]

Answer:

24.269

Step-by-step explanation:

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3 years ago
Select yes or no to indicate whether a zero must be written in the dividend to find the quotient
neonofarm [45]

Answer:

2.25 divided by 0.6 : Yes and 5.2 divided by 8, 3.63 divided by 3, 71.1 divided by 9 : No

Step-by-step explanation:

We have that when two numbers are divided, they can be written in the form \frac{p}{q}, where p is the dividend and q is the divisor.

Now, when we divide 5.2 by 8, we can write \frac{5.2}{8}

Also, the division 3.63 by 3, can be written as \frac{3.63}{3} = 1.21

Further, when we divide 71.1 by 3, we can write \frac{71.1}{3} = 23.7

We can see that above divisions are easy divisions and do not require to write any type of 0 in the numerator.

Moreover, when we divide 2.25 by 0.6, we can write \frac{2.25}{0.6} = \frac{2.25\times 10}{6}.

So, we get that in the last division, we need to write a zero in order to multiply the numerator with 10 for easy division.

Hence, 2.25 divided by 0.6 : Yes and 5.2 divided by 8, 3.63 divided by 3, 71.1 divided by 9 : No

3 0
3 years ago
Can some one please help me?
n200080 [17]

Answer: C

Step-by-step explanation: basicly all u have to do juss multilpy how many on top with the extra boxes, hope this helpss :)

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3 years ago
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