Step-by-step explanation:
9. log(2)=a, log(3)=b, then log(36)=______
log(36) = log(6*6) = log(6) + log(6)
log(36)= log(6) + log(6)
log(36) = log(3*2) + log(3*2)
log(36) = (log(3) + log(2)) + (log(3) + log(2))
log(36) = (a + b) + (b + a)
log(36) = a + b + b + a
log(36) = 2a + 2b
Hello!
Answer:
To solve, we will need to use Right-Triangle Trigonometry:
Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)
tan ∠S = a / (1/2b)
tan ∠S = 3√5 / 14
tan ∠S ≈ 0.479
arctan 0.479 = m∠S (inverse)
m∠S and m∠R ≈ 25.6°
Use cosine to solve for the hypotenuse, or the missing side-length:
cos ∠S = 14 / x
x · cos (25.6) = 14
x = 14 / cos(25.6)
x ≈ 15.52
Both triangles are congruent, so we can go ahead and find the perimeter of the figure:
RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.
Hope this helped you! :)
Answer:
D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.
Step-by-step explanation:
The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1
However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;
m=Δy/Δx where
m=the slope of the graph
Δy= 3-0 =3
Δx= 0--3 =3
m=3/3 = 1
The equation of the line should be;
m=Δy/Δx
1=y-3/x-0
1x= y-3
3+1x= y
y= 1x + 3 ----------where the slope is 1 and y-intercept is 3
So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>
While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>
<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>
Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.
Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3
Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.
