Answer:
a=35x−x^2
Step-by-step explanation:
Having
70 ft of fencing with a
width of x
feet and knowing the perimeter of a rectangle is
p=2w+2l
we can state the length of the garden as:
70=2x+2l
and solving for l
we know the length with be:
2l=70−2x or l=35−x
And then knowing the formula for the area of a rectangle is
a=w⋅l
we can write the equation as:
a=x⋅(35−x)a=35x−x^2
Answer:
two chop chop
Step-by-step explanation:
because it's more cheaper and money saving
Answer:
In 1 min a gazelle runs 3,900 ft.
As a fraction, 1/65
In order to find the solution to this problem you could use a table.
Since we are using seconds we have to convert the 1 min = 60 seconds.
<u>Sec</u><u> | 12 | 60</u>
<u>Fts</u><u> | 780 | x </u>
12 goes into 60 5 times, so we have to multiply 780 by 5 which gives us 3900.
x=3900
The answer is Pyrrophyta <span />
Answer: 0.0930
Step-by-step explanation:
As per given , we have
H0: μcoffee = 6
Ha: μcoffee < 6
She finds z = −1.68 with one-sided P-value P = 0.0465.
The P-value for two-tailed test is calculated by :
For z= -1.68 , we have
![=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)]](https://tex.z-dn.net/?f=%3D2%281-P%28z%5Cleq1.68%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D)
![=2(1-0.9535213)\ \ \ [\text{ NORM.S.DIST(z, TRUE}]\\\\=2( 0.0464787)=0.0929573\approx0.0930](https://tex.z-dn.net/?f=%3D2%281-0.9535213%29%5C%20%5C%20%5C%20%5B%5Ctext%7B%20NORM.S.DIST%28z%2C%20TRUE%7D%5D%5C%5C%5C%5C%3D2%28%200.0464787%29%3D0.0929573%5Capprox0.0930)
Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .
