What is the intermediate step in the form (x+a)^2=b(x+a)

Mathematics

1 answer:

Step2247 [10]2 years ago

7 0

Answer:

The intermediate step are;

1) Separate the constants from the terms in x² and x

2) Divide the equation by the coefficient of x²

3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression

Step-by-step explanation:

The function given in the question is 6·x² + 48·x + 207 = 15

The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;

6·x² + 48·x + 207 = 15

We get

1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192

6·x² + 48·x = -192

2) Dividing by 6 x² + 8·x = -32

3) Add the constant that completes the square to both sides

x² + 8·x + 16 = -32 +16 = -16

x² + 8·x + 16 = -16

4) Factorize (x + 4)² = -16

5) Compare (x + 4)² = -16 which is in the form (x + a)² = b

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Lapatulllka [165]

Answer:

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<u>I hope this is enough or u can get ur answer out of it :)</u>

8 0

2 years ago

I want to know the answer

butalik [34]

Let
A-----> the point (0.25,1)
B-----> the point (0.50,1.75)

we know that
the equation that represents the linear function is the equation of a line
so
step 1
find the slope m with the points A and B
m=(y2-y1)/(x2-x1)-----> m=(1.75-1)/(0.50-0.25)---> m=0.75/0.25--> m=3

step 2
with m=3 and point A (0.25,1)
find the equation of a line
y-y1=m*(x-x1)-------> y-1=3*(x-0.25)----> y=3x-0.75+1----> y=3x+0.25

the answer is
y=3x+0.25

see the attached figure